你好，我有一个批处理文件，如下所示：
if %day%==monday, tuesday, wednesday, thursday, friday (
goto yes
) else (
goto no
)
现在我知道第一行行不通。
我真正想要发生的事情：
它会自动检查现在是哪一天。如果是周一到周五，就必须去'yes'，否则（周六/周日）就去'no'。
如何做到这一点？
【问题讨论】：
标签： batch-file goto
这是一个示例 bat 文件，我相信您可以想到其他方法来使用此示例代码。例如，任何时候您都需要一个“in”列表。棘手的一点是 %date:~0,3% 这表示扩展 %date% 环境变量并从位置 0 开始字符串的开头返回接下来的 3 个字符。您可以从“set /?”中了解更多信息。命令。
示例：IsWeekDay.bat
@echo off
setlocal
for %%i in (Mon,Tue,Wed,Thu,Fri) do (
if "%date:~0,3%"=="%%i" goto YES
)
:NO
echo No
goto EOF
:YES
echo Yes
:EOF
endlocal
【讨论】：
我在网上遇到过这个。经过测试，它可以工作。以整数形式返回日期，您仍然可以使用它。
@For /F "tokens=2,3,4 delims=/ " %%A in ('Date /t') do @(
Set Month=%%A
Set Day=%%B
Set Year=%%C
)
@echo DAY = %Day%
@echo Month = %Month%
@echo Year = %Year%
【讨论】：
正如Jay 所提到的，使用date /t 仅适用于该命令输出星期几和日期的语言环境，而不适用于其他语言环境（例如俄语）。如果您不介意将批处理文件与一些 VBScript 混合使用，这里有一个适用于所有语言环境的解决方案。
诀窍是这个微小的 VBScript 脚本，它将星期几输出为数字（1 = 星期日，2 = 星期一，... 7 = 星期六）：
WScript.Echo DatePart("w", Date)
您可以从批处理文件运行此脚本，读取其输出并应用您的逻辑：
for /f %%d in ('cscript dayofweek.vbs //nologo') do (
if %%d==7 goto no :: Saturday
if %%d==1 goto no :: Sunday
)
goto yes
【讨论】：
IF %day% == monday GOTO YES
IF %day% == tuesday GOTO YES
IF %day% == wednesday GOTO YES
IF %day% == thursday GOTO YES
IF %day% == friday GOTO YES
GOTO NO
【讨论】：
我没有按要求回答问题的批处理 fu，但是，假设这是一个 Windows 批处理文件，请考虑使用任务调度程序执行脚本，这将让您设置您所询问的调度类型为。
【讨论】：
这是一个批处理文件，它以几乎与语言环境无关的方式提取星期几、星期几、月份和年份。
唯一特定于区域设置的是星期几的拼写，其余的与区域设置无关。
所以在英语中，它会在星期四返回 Thu，但在荷兰语中，它将是 do（用于 donderdag）。
:: http://stackoverflow.com/questions/203090/how-to-get-current-datetime-on-windows-command-line-in-a-suitable-format-for-usi
:: Works on any NT/2k machine independent of regional date settings
::
:: 20110103 - adapted by jeroen@pluimers.com for Dutch locale
:: 20110303 - adapted by jeroen@pluimers.com for day-of-week
:: Dutch will get jj as year from echo:^|date, so the '%%c' trick does not work as it will fill 'jj', but we want 'yy'
:: luckily, all countries seem to have year at the end: http://en.wikipedia.org/wiki/Calendar_date
:: set '%%c'=%%k
:: set 'yy'=%%k
::
:: Also, in Dutch, there is a difference between %date% and date/t: the former will not include
:: the day-of-the-week, but the latter will.
:: That means the if "%date%A" LSS "A" trick does not work with %date%, we need a loop
:: to check if the day-of-the-week needs us to take tokens 2-4 in stead of 1-3:
:: if "%date%A" LSS "A" (set toks=1-3) else (set toks=2-4)
:: for /f "tokens=1" %%t in ('date/t') do (...)
::
:: Another difference between Dutch and English is that the Dutch date/t will prepend the day of the week in a lower case 2-letter form.
:: So the LSS "A" trick needs to be replaced with an LSS "a" trick
:: if "%date%A" LSS "A" (set toks=1-3) else (set toks=2-4)
:: if "%%ta" LSS "a" (set toks=1-3) else (set toks=2-4)
::
:: In addition, date will display the current date before the input prompt using dashes
:: in Dutch, but using slashes in English, so there will be two occurances of the outer loop in Dutch
:: and one occurence in English.
:: This skips the first iteration:
:: if "%%a" GEQ "A"
::
:: echo:^|date
:: Huidige datum: ma 03-01-2011
:: Voer de nieuwe datum in: (dd-mm-jj)
:: The current date is: Mon 01/03/2011
:: Enter the new date: (mm-dd-yy)
::
:: date/t
:: ma 03-01-2011
:: Mon 01/03/2011
::
:: The assumption in this batch-file is that echo:^|date will return the date format
:: using either mm and dd or dd and mm in the first two valid tokens on the second line, and the year as the last token.
::
:: The outer loop will get the right tokens, the inner loop assigns the variables depending on the tokens.
:: That will resolve the order of the tokens.
::
@ECHO off
set v_day_of_week=
set v_day=
set v_month=
set v_year=
SETLOCAL ENABLEEXTENSIONS
for /f "tokens=1" %%t in ('date/t') do (
set v_day_of_week=%%t
if "%%ta" LSS "a" (set toks=1-3) else (set toks=2-4)
)
::DEBUG echo toks=%toks%
for /f "tokens=2-4 delims=(-)" %%a in ('echo:^|date') do (
::DEBUG echo first token=%%a
if "%%a" GEQ "A" (
for /f "tokens=%toks% delims=.-/ " %%i in ('date/t') do (
set '%%a'=%%i
set '%%b'=%%j
set 'yy'=%%k
)
)
)
if %'yy'% LSS 100 set 'yy'=20%'yy'%
set Today=%'yy'%-%'mm'%-%'dd'%
ENDLOCAL & SET day_of_week=%v_day_of_week% & SET v_year=%'yy'%& SET v_month=%'mm'%& SET v_day=%'dd'%
ECHO Today is Year: [%V_Year%] Month: [%V_Month%] Day: [%V_Day%]
set datestring=%V_Year%%V_Month%%V_Day%
echo %datestring%
echo day of week=%day_of_week%
:EOF
玩得开心！
--杰罗恩
【讨论】：
来自this answer，我们有
wmic path win32_localtime get dayofweek
根据this thread 中的建议对此进行扩展，我们可以如下设置 dayofweek 变量：
@echo off
REM Unset dayofweek in case set in a previous execution of this batch file
set dayofweek=
REM Get dayofweek into a variable. Locale-specific: 0 is either Sunday or Monday.
for /F "skip=1 tokens=*" %%a in ('wmic path win32_localtime get dayofweek') do if not defined dayofweek set dayofweek=%%a
echo %dayofweek%
请注意，0 可以是星期日或星期一，具体取决于您的语言环境。
【讨论】：