使用 libtool 构建 dll 时获取 exe答案

【问题标题】：Getting exe when building dll using libtool使用 libtool 构建 dll 时获取 exe
【发布时间】：2015-02-26 13:15:46
【问题描述】：

我正在尝试使用 MinGW 在 Windows 上编译 this 项目的 .dll。一切正常，除了一点：输出是 .exe 文件 - 不是 .dll。

这是 libtool 给我的通知：

*** Since this library must not contain undefined symbols,
*** because either the platform does not support them or
*** it was explicitly requested with -no-undefined,
*** libtool will only create a static version of it.

好吧，我在项目选项 -no-undefined 中没有找到任何地方，这就是为什么我想知道应该修复哪些符号（以及如何修复？？）才能得到需要 .dll？

也许链接器有一些问题？我不知道在哪里更改（$LIBRARY_PATH = /c/mingw 已经），这就是为什么在make 期间弹出此警告：

*** Warning: linker path does not have real file for library -lz.
*** I have the capability to make that library automatically link in when
*** you link to this library.  But I can only do this if you have a
*** shared version of the library, which you do not appear to have
*** because I did check the linker path looking for a file starting
*** with libz and none of the candidates passed a file format test
*** using a file magic. Last file checked: c:/Strawberry/c/bin/../lib/gcc/x86_64
-w64-mingw32/4.8.3/../../..//libz.a
*** The inter-library dependencies that have been dropped here will be
*** automatically added whenever a program is linked with this library
*** or is declared to -dlopen it.

【问题讨论】：

标签： c++ dll mingw ld libtool

【解决方案1】：

看起来您的程序需要 zlib，但 c:/Strawberry/c/bin/../lib/gcc/x86_64 -w64-mingw32/4.8.3/../../..//libz.a 无效（不同的目标架构 - x86 与 x86_64？）。你需要得到一个真正的zlib，为相同的架构编译并将你的程序指向它。

【讨论】：

【解决方案2】：

您可以使用具有以下内容的 .cmd 文件

::source code file path
set src_path=source.cpp

::output file path

set bin_path=yourlib.dll

::library you need

set libs=-lmingw32 -lkernel32 -lshell32 -luser32 -lwsock32 -lws2_32 -lole32 -loleaut32

::windows subsystem

set sub_sys=-mwindows

::cpp version used by g++

set cpp_ver=-std=c++1y

::jump to g++ path

cd "%your_mingw32_folder_path%\bin\"

::run g++ with args

g++.exe "%src_path%" -o "%bin_path%" -Wall -W -w -static %sub_sys% %libs% %cpp_ver%


pause

【讨论】：