【发布时间】:2018-08-16 14:46:09
【问题描述】:
我想执行多个线程,这些线程将尝试同时添加到我的自定义列表 MyList,但是当我尝试获取计数时我没有看到任何输出
public static void main(String[] args) {
MyList<String> list = new list<String>();
MyRunner<String> myRunner = new MyRunner<String>(list);
ExecutorService threadPool = Executors.newFixedThreadPool(4);
for(int i = 0; i < 20; i++) {
CompletableFuture.runAsync(new MyRunner<String>(list));
}
try {
threadPool.awaitTermination(100l, TimeUnit.SECONDS);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println(list.getCount());
}
跑步者类:
class MyRunner<String> implements Runnable {
MyList<String> list;
public MyRunner(MyList <String> t) {
this.list = t;
}
@Override
public void run() {
for(int i = 0; i < 200; i++) {
list((String) (i + Thread.currentThread().getName()));
}
}
}
类我的列表:
public class MyList<T> {
Queue<T> blockingQueue;
Lock lock;
long count;
public MyList() {
blockingQueue = new LinkedList<>();
count = 0;
lock = new ReentrantLock();
}
public void add(T singleTon) {
lock.lock();
blockingQueue.offer(singleTon);
count +=1;
lock.unlock();
}
public long getCount() {
return count;
}
}
跟进问题:
使用CountDownLatch 程序没有结束。 sysout 的数量是 10001,最后一个输出是 In runnable: 9 : pool-1-thread-1
CountDownLatch 实现:
public static void main(String[] args) throws InterruptedException {
MyList<String> mylist = new MyList<>();
CountDownLatch latch = new CountDownLatch(10);
ExecutorService executorService = Executors.newFixedThreadPool(4);
for(int i = 0; i < 1000; i++) {
CompletableFuture.runAsync(new MyRunner<String>(mylist, latch), executorService);
}
latch.await();
System.out.println(mylist.count);
}
class MyRunner<String> implements Runnable {
MyList<String> mylist;
CountDownLatch latch;
public MyRunner(MyList<String> mylist, CountDownLatch latch) {
this.latch = latch;
this.mylist = mylist;
}
@Override
public void run() {
for(int i = 0; i < 10; i++) {
System.out.println("In runnable: "+ i + " : "+ Thread.currentThread().getName());
mylist.add((String)("" + i));
}
latch.countDown();
}
}
【问题讨论】:
-
提示:你在使用那个线程池吗? IDE 会告诉你...
-
请发帖minimal reproducible example。您发布的代码不仅无法编译,而且不包含重要信息,例如您的列表实现。
-
@assylias :已编辑问题。它现在还包括
CountDownLatch实现。 -
Latch 有计数
10,你循环1000次。看到问题了吗?此外,您永远不会shutdownExecutorService并且您的线程不是守护进程,因此程序永远不会完成。 -
就是这样!如果倒计时少于 Runnables 的数量,可能是关于 CountDownLatch 行为的后续问题(或将在新线程中发布)
标签: java concurrency java-8 java.util.concurrent