【发布时间】:2019-10-11 14:54:28
【问题描述】:
所以我创建了程序的一部分,它应该从文本文件中读取。问题是它只读取前两行(完美无瑕),当它第二次循环时tempLine 是“”。正因为如此,我得到了 ArrayIndexOutOfBoundsException。为什么会这样?
每个人有 2 行。这些被添加到列表中。
文件如下所示:
7603021234, Alhambra Aromes
2018-07-01
8104021234, Bear Belle
2018-12-02
8512021234, Chamade Coriola
2017-03-12
7608021234, Diamanda Djedi
2019-01-30
7605021234, Elmer Ekorrsson
2010-04-07
7911061234, Fritjoff Flacon
1999-12-16
1111111111, Greger Ganache
2019-03-23
5711121234, Hilmer Heur
2019-08-18
2222222222, Ida Idylle
2017-03-07
1212121212, Jicky Juul
2018-09-27
4604151234, Kadine Karlsson
2018-01-09
9110261234, Liu Lingren
2018-02-15
7907281234, Mitsuko Mayotte
2018-12-22
7805211234, Nahema Ninsson
2019-01-04
这是我的源代码:
public class ReadFile {
private List<Customer> allMembers = new LinkedList<>();
public void readFile () throws IOException {
String tempLine;
String[] tempString;
String personalNumber;
String firstName;
String lastName;
LocalDate lastPayed;
Path inFilePath = Paths.get("C:\\Users\\Allan\\Documents\\Nackademin\\OOP\\Inlämningsuppgift2\\customers.txt");
Scanner fileScanner = new Scanner(inFilePath);
while(fileScanner.hasNext()) {
tempLine = fileScanner.nextLine();
tempString = tempLine.split(" ");
personalNumber = tempString[0].replace(",", "");
firstName = tempString[1];
lastName = tempString[2];
if (fileScanner.hasNext()) {
lastPayed = LocalDate.parse(fileScanner.next());
allMembers.add(new Customer(personalNumber, firstName, lastName, lastPayed));
}
}
}
public List<Customer> getAllMembers() {
return allMembers;
}
}
【问题讨论】:
-
试试改成
lastPayed = LocalDate.parse(fileScanner.nextLine()); -
成功了!但是为什么???
-
我相信
next()将换行符留在扫描仪的输入缓冲区中,但nextLine()使用它。所以在第二次迭代中tempLine = fileScanner.nextLine();正在读取第二行末尾的换行符并返回一个空字符串。
标签: java while-loop text-files java.util.scanner