限制分页页码

Question

$objConnect = mysql_connect("localhost","root","") or die(mysql_error());
$objDB = mysql_select_db("Test");

$strSQL = "SELECT * FROM UserAddedRecord WHERE (Name LIKE '%".$getname."%' and State LIKE '%".$getstate."%' and Cell LIKE '%".$getcell."%' and Custgroup LIKE '%".$getgroup."%') AND user_id=$id";

$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
$Num_Rows = mysql_num_rows($objQuery);

$Per_Page = 5;   

if (!isset($_GET['Page'])) {
    $Page = 1;
} else {
    $Page = $_GET['Page'];
}

$Prev_Page = $Page - 1;
$Next_Page = $Page + 1;

$Page_Start = (($Per_Page * $Page) - $Per_Page);
if ($Num_Rows <= $Per_Page) {
    $Num_Pages = 1;
} elseif (($Num_Rows % $Per_Page) == 0) {
    $Num_Pages = ($Num_Rows / $Per_Page) ;
} else {
    $Num_Pages = ($Num_Rows / $Per_Page) + 1;
    $Num_Pages = (int) $Num_Pages;
}


$strSQL .=" order  by addedrec_ID DESC LIMIT $Page_Start , $Per_Page";
$objQuery  = mysql_query($strSQL) or trigger_error(mysql_error());;

if ($Prev_Page) {
    echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Prev_Page&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'><< Back</a> ";
}

for ($i=1; $i <= $Num_Pages; $i++) {
    if ($i != $Page) {
        echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$i&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'>$i</a> ";
    } else {
        echo "<b> $i </b>"; 
    }
}

if ($Page!=$Num_Pages) {
    echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Next_Page&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'>Next>></a> ";        
}

mysql_close($objConnect);

这是我用来为数据搜索创建分页页面的代码。但我只是注意到我有太多的记录，那么它就会有太多的页码。我正在尝试限制显示的页码，并寻找很多例子..它有很多方法可以做到，但我仍然不知道如何限制我的方法......

Answer 1

好吧，如果你的意思是显示类似的东西

Prev 1 2 3 4 5 6 .. 40 41 Next 
Prev 1 2 .. 6 7 8 9 10 .. 40 41 Next

首先我们需要创建一个函数来处理我们需要输出分页的内容。这是我使用的一个功能，效果很好。

function get_paging_info($tot_rows,$pp,$curr_page)
{
    $pages = ceil($tot_rows / $pp); // calc pages

    $data = array(); // start out array
    $data['si']        = ($curr_page * $pp) - $pp; // what row to start at
    $data['pages']     = $pages;                   // add the pages
    $data['curr_page'] = $curr_page;               // Whats the current page

    return $data; //return the paging data

}

现在这个功能非常可靠，对我来说效果很好。

所以你传递了这个函数

• $tot_rows = 计算的查询行数
• $pp = 每页项目数
• $curr_page = 当前页码

好的，现在您有了所需的数据，您需要显示它。

这是我使用的内容，请在您思考“啊，太长了”之前先阅读它。其实很简单。

这是它将返回的快照

    <!-- Create the query -->
    <?php $count = mysql_fetch_assoc( mysql_query ( "SELECT COUNT( rows ) as count FROM table" ) ) ;

    <?php $count = $count[0]['count']; ?>

<!-- Call our function from above -->
<?php $paging_info = get_paging_info($count,5,34); ?>


<p>
    <!-- If the current page is more than 1, show the First and Previous links -->
    <?php if($paging_info['curr_page'] > 1) : ?>
        <a href='' title='Page 1'>First</a>
        <a href='' title='Page <?php echo ($paging_info['curr_page'] - 1); ?>'>Prev</a>
    <?php endif; ?>



    <?php
        //setup starting point

        //$max is equal to number of links shown
        $max = 7;
        if($paging_info['curr_page'] < $max)
            $sp = 1;
        elseif($paging_info['curr_page'] >= ($paging_info['pages'] - floor($max / 2)) )
            $sp = $paging_info['pages'] - $max + 1;
        elseif($paging_info['curr_page'] >= $max)
            $sp = $paging_info['curr_page']  - floor($max/2);
    ?>

    <!-- If the current page >= $max then show link to 1st page -->
    <?php if($paging_info['curr_page'] >= $max) : ?>

        <a href='' title='Page 1'>1</a>
        ..

    <?php endif; ?>

    <!-- Loop though max number of pages shown and show links either side equal to $max / 2 -->
    <?php for($i = $sp; $i <= ($sp + $max -1);$i++) : ?>

        <?php
            if($i > $paging_info['pages'])
                continue;
        ?>

        <?php if($paging_info['curr_page'] == $i) : ?>

            <span class='bold'><?php echo $i; ?></span>

        <?php else : ?>

            <a href='' title='Page <?php echo $i; ?>'><?php echo $i; ?></a>

        <?php endif; ?>

    <?php endfor; ?>


    <!-- If the current page is less than say the last page minus $max pages divided by 2-->
    <?php if($paging_info['curr_page'] < ($paging_info['pages'] - floor($max / 2))) : ?>

        ..
        <a href='' title='Page <?php echo $paging_info['pages']; ?>'><?php echo $paging_info['pages']; ?></a>

    <?php endif; ?>

    <!-- Show last two pages if we're not near them -->
    <?php if($paging_info['curr_page'] < $paging_info['pages']) : ?>

        <a href='<?php echo str_replace('/page'.$paging_info['curr_page'], '', $paging_info['curr_url']) . '/page'.($paging_info['curr_page'] + 1); ?>' title='Page <?php echo ($paging_info['curr_page'] + 1); ?>'>Next</a>

        <a href='<?php echo str_replace('/page'.$paging_info['curr_page'], '', $paging_info['curr_url']) . '/page'.$paging_info['pages']; ?>' title='Page <?php echo $paging_info['pages']; ?>'>Last</a>

    <?php endif; ?>
</p>

Answer 2

$count_pages = ceil($total / $items_per_page);

Answer 3

我在这里用非常相似的脚本为其他人解决了一个非常相似的问题：How to limit pages shown in pagination script

此外，我注意到您的脚本还有一些其他异常（除了我修复的不可读格式）。您应该将所有出现的$_SERVER[SCRIPT_NAME] 更改为$_SERVER['SCRIPT_NAME']。例如，在您的脚本中：

echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=...";

会变成：

echo " <a href ='{$_SERVER['SCRIPT_NAME']}?Page=...";

Answer 4

简单点，代码如下：

<?php       
    //put this code on the begining of the page
    $page=$_GET['page']; //Getting page number from url | example: www.mydomain.com/index.php?page=3
    if(!is_numeric($page)) $page=1; //If there is no page number specified we set number 1
$queryCount = "SELECT * FROM table "; //select from db
$query = $DB->query( $queryCount);
    $num = mysql_num_rows ($query); //count num rows
    $per_page=5; //default 5 results per page
$start=$per_page*($page-1); //start for select on next page (page2, 3, 4,5)
$end=min($num,$page*$per_page); //end


//here is select for your results. Be careful for LIMIT in the select!
$query = "SELECT * FROM page LIMIT $start, $per_page ";


//page bottom, where you want to put your numbers
$pages=ceil($num/$per_page);
  for($s=1; $s<=$pages; $s++)
  {
    if($s==$page)
      $numPage  .= "[$s] ";
    else
      $numPage  .= "<a href='index.php?page=$s'>$s</a> ";
  }

echo $numPage;

?>

我没有测试它，但我认为它必须工作:-)

问候，伊万

Answer 5

我的代码总是显示至少 9 页，以防总页数>9 无论您在第 1、2、3 页上是什么

<ul class="pagination pagination-sm" style="align:center">
    <li><a href="./?page=1"><</span></a></li>
    <?php
    if ($current_page <4){
        if ($total_pages<9)
        {
            for($i = 1; $i <=  $total_pages; $i++)
            {

                if ($i == $current_page)
                {
                    echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
                } else {
                    echo ' <li><a href="./?page='.$i.'">'; echo $i.'</a></li>'."\n";
                }
            }
        }
        else
        {
            for($i = 1; $i <=  9; $i++)
            {

                if ($i == $current_page)
                {
                    echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
                } else {
                    echo ' <li><a href="./?trang='.$i.'">'; echo $i.'</a></li>'."\n";
                }
            }
        }
    }
    elseif ($current_page >$total_pages-4)
    {
        if ($total_pages<9)
        {
            for($i = 1; $i <=  $total_pages; $i++){

                if ($i == $current_page){
                    echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
                } else {
                    echo ' <li><a href="./?page='.$i.'">'; echo $i.'</a></li>'."\n";
                }
            }
        }else{
            for($i = $total_pages-8; $i <=  $total_pages; $i++){

                if ($i == $current_page){
                    echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
                } else {
                    echo ' <li><a href="./?page='.$i.'">'; echo $i.'</a></li>'."\n";
                }
            }
        }

    }else{
        for($i = max(1, $current_page - 4); $i <= min($current_page + 4, $total_pages); $i++){

            if ($i == $current_page){
                echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
            } else {
                echo ' <li><a href="./?trang='.$i.'">'; echo $i.'</a></li>'."\n";
            }
        }
    }
    ?>
    <li>
        <a href="./?trang=<?php echo $total_pages ?>">></a>
    </li>
</ul>

Answer 6

您需要在 sql 语句中使用 LIMIT 子句。例如：

SELECT <column> 
  FROM <table>
    LIMIT 0, 5

参考：SELECT Syntax

Answer 7

此代码的目的只是显示分页中确定的（特定）页数

从url获取当前页码并定义$curr_pg_numb

从mysql获取总页数并定义$total_pages

这是分页的代码

$counter=0;
$init_num_to_left = 3;//initial number of pages to show to left from current page
$init_num_to_right = 4;

if( $curr_pg_numb - $init_num_to_left < 1 ){
$init_num_to_right = $init_num_to_right + ( 1 - ($curr_pg_numb - $init_num_to_left) );
$init_num_to_left = $curr_pg_numb - 1;
}
else if( $curr_pg_numb + $init_num_to_right > $total_pages ){
$init_num_to_left = $init_num_to_left + ( ($curr_pg_numb + $init_num_to_right) - $total_pages );
$init_num_to_right = ($curr_pg_numb + $init_num_to_right) - $total_pages;
}

while($counter <= $total_pages ) {
  if ( $counter > 0 ){
    if ($curr_pg_numb==$counter){
    echo '<strong> '. ( htmlspecialchars($curr_pg_numb , ENT_QUOTES, "UTF-8") + 0 ). '</strong> ';
    }
    else {
    if ( $counter >= ($curr_pg_numb - $init_num_to_left ) and $counter <= ($curr_pg_numb + $init_num_to_right ) ) {
    echo '<a href="?cpn='. htmlspecialchars(($counter), ENT_QUOTES, "UTF-8"). '" style="margin:5px;">'. htmlspecialchars(($counter), ENT_QUOTES, "UTF-8"). '</a>';
    }
    }//else {
  }//if ( $counter > 0 ){
$counter++;
}//while($counter <= $total_pages ) {