【发布时间】:2019-01-08 19:59:39
【问题描述】:
我必须编写一个程序来监视两个命名管道并打印通过其中一个发送的信息。
当其中一个管道的写端关闭时,程序会检测到这一点并再次关闭和打开管道。
这是我目前所写的:
#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <fcntl.h>
#define BUF_SIZE 200
int
main(void)
{
fd_set rfds;
struct timeval tv;
int retval;
ssize_t n_read;
char buf[BUF_SIZE];
/* Open pipes */
int tuberia1_fd = open("tuberia1",O_RDONLY);
int tuberia2_fd = open("tuberia2",O_RDONLY);
while(1){
/* Watch stdin (fd 0) to see when it has input. */
FD_ZERO(&rfds);
FD_SET(0, &rfds);
/* Wait for an indefinite amount of time. */
tv.tv_sec = 0;
tv.tv_usec = 0;
retval = select(2, &rfds, NULL, NULL, &tv);
/* Don't rely on the value of tv now! */
if (retval == -1)
perror("select()");
exit(EXIT_FAILURE);
if(FD_ISSET(tuberia1_fd, &rfds)){
n_read = read(tuberia1_fd, &buf, BUF_SIZE);
if (n_read == 0){
close(tuberia1_fd);
tuberia1_fd = open("tuberia1", O_RDONLY);
}else{
buf[n_read] = '\0';
printf("tuberia1: %s", buf);
}
} else if (FD_ISSET(tuberia2_fd, &rfds)){
n_read = read(tuberia2_fd, &buf, BUF_SIZE);
if (n_read == 0){
close(tuberia2_fd);
tuberia2_fd = open("tuberia2", O_RDONLY);
}else{
buf[n_read] = '\0';
printf("tuberia2: %s", buf);
}
}
}
}
当我运行它时,程序会锁定,这是预期的行为。但是当我echo hello_world > tuberia1 时,程序没有响应。
发生了什么事?
编辑:正如下面 GM 所观察到的,我错误地将参数传递给 select。修复后我的程序如下所示:
#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <fcntl.h>
#define BUF_SIZE 200
int
main(void)
{
fd_set rfds;
struct timeval tv;
int retval;
ssize_t n_read;
char buf[BUF_SIZE];
/* Open pipes */
printf("Opening tuberia1");
int tuberia1_fd = open("tuberia1",O_RDONLY);
printf("Opening tuberia2");
int tuberia2_fd = open("tuberia2",O_RDONLY);
while(1){
printf("Enter the loop");
/* Watch stdin (fd 0) to see when it has input. */
FD_ZERO(&rfds);
FD_SET(tuberia1_fd, &rfds);
FD_SET(tuberia2_fd, &rfds);
/* Wait for an indefinite amount of time. */
tv.tv_sec = 5;
tv.tv_usec = 0;
int fd_max = (tuberia1_fd > tuberia2_fd) ? tuberia1_fd : tuberia2_fd;
retval = select(fd_max, &rfds, NULL, NULL, &tv);
/* Don't rely on the value of tv now! */
if (retval == -1)
perror("select()");
exit(EXIT_FAILURE);
if(FD_ISSET(tuberia1_fd, &rfds)){
n_read = read(tuberia1_fd, &buf, BUF_SIZE);
if (n_read == 0){
close(tuberia1_fd);
tuberia1_fd = open("tuberia1", O_RDONLY);
}else{
buf[n_read] = '\0';
printf("tuberia1: %s", buf);
}
} else if (FD_ISSET(tuberia2_fd, &rfds)){
n_read = read(tuberia2_fd, &buf, BUF_SIZE);
if (n_read == 0){
close(tuberia2_fd);
tuberia2_fd = open("tuberia2", O_RDONLY);
}else{
buf[n_read] = '\0';
printf("tuberia2: %s", buf);
}
}
}
}
还是不行。在 GDB 下运行它表明程序永远不会超过第一个 open。
【问题讨论】:
-
如果你在调试器中运行你的程序,我相当有信心你会看到执行
echo命令会导致你的程序通过第一个open(),只会阻塞第二个一。
标签: c pipe named-pipes