将对象数组减少/过滤为新的对象数组。 [复制]答案

【问题标题】：Reduce/Filter array of objects into new array of objects. [duplicate]将对象数组减少/过滤为新的对象数组。 [复制]
【发布时间】：2018-02-14 15:37:42
【问题描述】：

假设我有一个对象数组，我需要使用以前的数据创建一个新的对象数组。就我而言，我不需要过滤所有数据。什么是 ES6 的最佳解决方案。

data = [{
 deviceId:1
 deviceStatus:"Offline"
 deviceType:"Tag"
 isConfigured:true
 isEnabled:true
 isLocalized:false
 isMasterAssigned:false
 lastAliveMessage:null
 location:{roomId: 5, name: "Room_207", zones: null, plan: null}
 name:"Tag For sending an alarm"
},{
 deviceId:2
 deviceStatus:"Online"
 deviceType:"Tag"
 isConfigured:true
 isEnabled:true
 isLocalized:false
 isMasterAssigned:false
 lastAliveMessage:null
 location:{roomId: 6, name: "Room_208", zones: null, plan: null}
 name:"Some Text"
}]

我只需要过滤需要的数据。

filteredData=[{
     deviceId:2
     deviceStatus:"Online"
     deviceType:"Tag"
     lastAliveMessage:null
     name: 'name:"Some Text'
     location: location.name
},{
     deviceId:2
     deviceStatus:"Online"
     deviceType:"Tag"
     lastAliveMessage:null
     name: 'name:"Some Text'
     location: location.name
}]

【问题讨论】：

标签： javascript arrays filter ecmascript-6

【解决方案1】：

使用Array#map 函数迭代它们并创建另一种类型的对象。

const data = [{
    deviceId:1,
    deviceStatus:"Offline",
    deviceType:"Tag",
    isConfigured:true,
    isEnabled:true,
    isLocalized:false,
    isMasterAssigned:false,
    lastAliveMessage:null,
    location:{roomId: 5, name: "Room_207", zones: null, plan: null},
    name:"Tag For sending an alarm"
},{
    deviceId:2,
    deviceStatus:"Online",
    deviceType:"Tag",
    isConfigured:true,
    isEnabled:true,
    isLocalized:false,
    isMasterAssigned:false,
    lastAliveMessage:null,
    location:{roomId: 6, name: "Room_208", zones: null, plan: null},
    name:"Some Text"
}];

const newObj = data.map(item => ({
  deviceId: item.deviceId,
  deviceStatus: item.deviceStatus,
  deviceType: item.deviceType,
  lastAliveMessage: item.lastAliveMessage,
  name: item.name,
  location: item.location.name
}));

console.log(newObj);

【讨论】：

这个问题应该被标记为重复。
所以投票关闭它而不是评论答案@Alexandru-IonutMihai

【解决方案2】：

您可以为想要的密钥创建一个白名单。

var data = [{ deviceId: 1, deviceStatus: "Offline", deviceType: "Tag", isConfigured: true, isEnabled: true, isLocalized: false, isMasterAssigned: false, lastAliveMessage: null, location: { roomId: 5, name: "Room_207", zones: null, plan: null }, name: "Tag For sending an alarm" }, { deviceId: 2, deviceStatus: "Online", deviceType: "Tag", isConfigured: true, isEnabled: true, isLocalized: false, isMasterAssigned: false, lastAliveMessage: null, location: { roomId: 6, name: "Room_208", zones: null, plan: null }, name: "Some Text" }], 
    keys = ['deviceId', 'deviceStatus'],
    result = data.map(o => Object.assign(...keys.map(k => ({ [k]: o[k] }))));

console.log(result);

【讨论】：