【发布时间】：2013-06-12 23:25:44
【问题描述】：
我正在尝试编写一个简单的程序来通过 hterm 获取用户的输入，当用户输入“电机”和“25”时，电机将以顺时针方向旋转 25 和逆时针方向旋转 25
//Define clock-speed and include necessary headers
#define F_CPU 1000000
#include <avr/io.h>
#include <util/delay.h>
#include <inttypes.h>
#include <avr/io.h>
#include <stdlib.h>
#include <avr/interrupt.h>
#include <stdio.h>
#include <stdint.h>
#include <util/delay.h>
#include <ctype.h>
#define F_CPU 16000000UL
#define BAUD 9600UL
char cmd[40];
void uart_init(void) // initializing UART
{
UBRRH = 0;
UBRRL = ((F_CPU+BAUD*8)/(BAUD*16)-1);
UCSRC |= 0x86; // 8N1 Data
UCSRB = 0x18; // Receiving and Transmitting
}
int uart_putch(char ch, FILE *stream) // Function for sending Data to PC
{
if (ch == '\n')
uart_putch('\r', stream);
while (!(UCSRA & (1<<UDRE)));
UDR=ch;
return 0;
}
int uart_getch(FILE *stream) // Function for receiving Data from PC
{
unsigned char ch; while (!(UCSRA & (1<<RXC)));
ch=UDR;
uart_putch(ch,stream); // Echo the output back to the terminal
return (tolower(ch));
}
FILE uart_str = FDEV_SETUP_STREAM(uart_putch, uart_getch, _FDEV_SETUP_RW); // Important, not deleting
void loeschen() // Delete the String
{
int strnglen = 0;
while (strnglen < 41 && cmd[strnglen] != 0)
{
cmd[strnglen]= 0;
strnglen++;
}
}
// Define the stepping angle
// Note: Divide by 2 if you are doing half-stepping. for filter test 1.8 defult
#define MIN_STEP 1.8
/* Define an array containing values to be sent at the required Port - for Full-stepping
<first four bits> - <last four bits> = <decimal equivalent>
00000001 = 1 ; 01000000 = 4
00000100 = 4 ; 00010000 = 16
00000010 = 2 ; 00001000 = 8
00001000 = 8 ; 00100000 = 32
*/
unsigned short control_array_full[4] = {4,16,8,32};
/* Define an array containing values to be sent at the required Port - for Half-stepping
<first four bits> - <last four bits> = <decimal equivalent>
0000-1001 = 8 + 1 = 9 ; 0010-0100 = 32 + 4 =36
0000-0001 = 1 ; 0000-0100 = 4
0000-0101 = 4 + 1 = 5 ; 00010100 = 16 + 4 = 20
00000100 = 4 ; 00010000 = 16
00000110 = 4 + 2 = 6 ; 00011000 = 16+8=24
0000-0010 = ; 00-001000 = 8
0000-1010 = 8 + 2 = 10 ; 00-101000 = 40
0000-1000 = 8 ; 00-100000 = 32
*/
unsigned short control_array_half[8] = {36,4,20,16,24,8,40,32};
// Adjust this delay to control effective RPM
// Do not make it very small as rotor will not be able to move so fast
// Currently set at 100ms
void delay()
{
_delay_ms(100);
}
void move_clockwise(unsigned short revolutions){
int i=0;
for (i=0; i < (revolutions* 360 /MIN_STEP) ; i++)
{
//Note: Take modulo (%) with 8 when half-stepping and change array too
PORTD = control_array_half[i % 4];
delay();
}
}
void move_anticlockwise(unsigned short revolutions){
int i;
for (i = (revolutions* 360 /MIN_STEP); i > 0 ; i--){
//Note: Take modulo (%) with 8 when half-stepping and change array too
PORTD = control_array_half[i % 4];
delay();
}
}
int main()
{
// Enter infinte loop
// Make changes here to suit your requirements
uart_init(); // initializing UART
stdout = stdin = &uart_str; // Necessary to compare whole Strings
while(1){
scanf("%s",&cmd); // Read String from Data Register
printf ("Please enter number of motor rotation for clockwise and anticlockwise");
items_read = scanf ("%d", &numbers[i]); // Read integer for motor revolution
if(strcmp(cmd, "motor") == 0)
{
DDRD = 0b00111110; //Set PORTD 4 bits for output
//Enter number of revolutions required in brackets
move_clockwise(items_read);
move_anticlockwise(items_read);
}
DDRD = 0b00000000;
}
loeschen();
}
现在，问题是我什么时候会从 main() 中删除这些行
items_read = scanf ("%d", &numbers[i]);
scanf ("%d",&i);
& 将 move_clockwise(items_read); 中的 items_read 设为：
move_clockwise(25);
move_anticlockwise(25);
然后当用户输入“电机”然后电机正在运行move_clockwise(25); 但move_anticlockwise(25); 没有运行，我想要的是同时使用“电机”，顺时针的数字和逆时针的数字......
如果有人可以帮助我，我将不胜感激！ 提前致谢！
【问题讨论】：
-
您的程序的某些部分（例如用于收集字符串）似乎丢失了。但也许你应该先做一个更简单的测试用例，去掉除了两个移动命令之外的所有东西。如果您以其他顺序发出它们，先逆时针，还是单独调用它们会发生什么？或者您可以制作一个初步测试程序，该程序在收到每个连续字符时前进一次。
-
我尝试只使用 scanf 和 printf，scanf 正在工作，但 printf 或 puts 都不适合我！！，谁能告诉我我在这里做错了什么我也想要用户的 int