如何使用 Java 代码获取服务器上文件的路径？

Question

我已在服务器“www.server.com”上上传了一个文件。现在我想通过java代码知道文件在同一台服务器上的路径。有没有具体的方法或流程？我是新手。

public class Test {   
    public static void main(String[] args) {
        test test = new test();
        String server ="www.server.com";
        int port = 21;
        String username = "abc";
        String password = "abc`enter code here`";

        FTPClient ftpclient = new FTPClient();


        try {
            ftpclient.connect(server, port);
            ftpclient.login(username, password);
            ftpclient.enterLocalPassiveMode();
            ftpclient.setFileType(FTP.BINARY_FILE_TYPE);

            File firstLocalFile = new File("D:\\ADF\\Tax Files\\TERData.zip");

            String firstRemoteFile = "TERData.zip";

            InputStream inputstream = new FileInputStream(firstLocalFile);
            System.out.println("Start Uploading the First File");

            System.out.println(" File Path ":+firstLocalFile.getAbsolutePath());

            boolean done = ftpclient.storeFile(firstRemoteFile, inputstream);

            if(done){
                System.out.println(" File successfully uploaded ");
            }                              
        } catch (IOException e) {
            // TODO: Add catch code
            System.out.println("Error: " + e.getMessage());
            e.printStackTrace();
        }

    }
}

Answer 1

    FTPClient ftpClient = new FTPClient();
            try {

                ftpClient.connect(server, port);
                ftpClient.login(user, pass);
                ftpClient.enterLocalPassiveMode();
                ftpClient.setFileType(FTP.BINARY_FILE_TYPE);

                 FTPFile[] files1 = ftpClient.listFiles("/test");//"/test/test.txt";
String remoteFile1 =files1[0].getName();
                File downloadFile1 = new File("D:/Downloads/test.mp4");
                OutputStream outputStream1 = new BufferedOutputStream(new FileOutputStream(downloadFile1));
                boolean success = ftpClient.retrieveFile(remoteFile1, outputStream1);
                outputStream1.close();

                if (success) {
                    System.out.println("File #1 has been downloaded successfully.");
                }