【发布时间】：2014-09-24 21:22:10
【问题描述】：
这是我需要输入的示例文本文件：
12 JackSprat 2 1 65000
13 HumptyDumpty 5 3 30000
17 BoPeep 2 3 30000
20 BoyBlue 3 2 58000
0
我得到的错误是一个声明错误，但我确实声明了我的指针：
C:employeeDatabase.c||在函数'printlist'中:| |82|错误：'current'之前的预期声明说明符|
这是我目前的代码：
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define NAME_LENGTH 20
typedef struct employeeData //employee struct declaration
{
int EMP_ID;
char* name;
int dept;
int rank;
double salary;
struct employeeData *next;
}employee;
employee* initializeList( int EMP_ID, char* name, int dept, int rank, double salary ) //initialize LL function for employees
{
employee* tmp = ( employee* )( malloc(sizeof(struct employeeData ) ) );
tmp->name = ( char* )malloc( sizeof( char )*NAME_LENGTH );
strcpy( tmp->name, name );
tmp->salary = salary;
tmp->EMP_ID = EMP_ID;
tmp->dept = dept;
tmp->rank = rank;
tmp->next = NULL;
return tmp;
}
employee* insertEmp( employee* head, employee* tmp ) //function to insert employees into the LL
{
employee* current = NULL;
current = head;
if( current == NULL || strcmp( current->name, tmp->name ) > 0) // checking order
{
tmp->next = current;
return tmp;
}
else
{
while( current->next != NULL && strcmp( current->next->name, tmp->name ) < 0 ) //changing order
{
current = current->next;
}
}
tmp->next = current->next;
current->next = tmp;
return head;
}
void query( employee *head, int submenu ) //query by employee rank function
{
printf( "\nEMP name\n" );
employee* current;
current = head;
while ( current != NULL )
{
if( current->rank == submenu )
{
printf( "%s\n", current->name );
if( current->next == NULL )
{
break;
}
current = current->next;
}
current = current->next;
}
return;
}
void printlist( employee* head ) //print result function HERE IS WHERE MY PROBLEM IS
employee* current;
current = head;
printf( "EMP_ID\t EMP NAME\t\t DEPT\t\t RANK\t\t SALARY " );
while ( current != NULL )
{
printf( "\n%d\t %s \t\t %d\t\t %d\t\t %d\n", current->EMP_ID, current->name, current->dept, current->rank, current->salary );
current = current->next;
}
return;
}
int main( void )
{
FILE* data = fopen( "empInfo.txt", "r" ); //read in emp data here
int EMP_ID, dept, rank, menu_choice = -1, submenu;
double salary;
char* name = ( char* )malloc( sizeof( char* )*NAME_LENGTH );
employee *head = NULL;
while( !feof( data ) ) //initialize the list by calling its function
{
fscanf( data, "%d %s %d %d %d", &EMP_ID, name, &dept, &rank, &salary );
{
if ( EMP_ID == 0 )
break;
}
employee* hold = initializeList( EMP_ID, name, dept, rank, salary );
head = insertEmp( head, hold );
}
while ( menu_choice != 0 ) //Menu declaration and listed choices
{
printf( "\nPlease select an action from the following menu\n" );
printf( "1 to add a new employee\n" );
printf( "2 to delete an employee\n" );
printf( "3 to modify an employee record\n" );
printf( "4 to query employees by rank\n" );
printf( "5 to print all employee information\n" );
printf( "0 to exit the program\n" );
scanf( "%d", &menu_choice );
if( menu_choice == 1 )
{
printf( "Choice 1\n" );
menu_choice = -1;
}
if ( menu_choice == 2 )
{
printf( "Choice 2\n" );
menu_choice = -1;
}
if ( menu_choice == 3 )
{
printf( "Choice 3\n" );
menu_choice = -1;
}
if ( menu_choice == 4 )
{
printf( "Please provide the rank of the employee you would like to query.\n" );
scanf( "%d", &submenu );
query( head, submenu );
menu_choice = -1;
}
if ( menu_choice == 5 )
{
printlist( head );
menu_choice = -1;
}
}
fclose( data );
while (getchar () != '\n') //I use this instead of system ("PAUSE")
getchar ();
return 0;
}
【问题讨论】：
-
在函数体的开头忘记
{。 -
注意：如果您要保持固定的缓冲区长度，这：
sizeof( char )*NAME_LENGTH毫无意义。您也可以将struct employeeData的char *name成员声明为char name[NAME_LENGTH];，因为无论如何您都在动态分配结构。而current->salary是double，通过%d格式说明符发送printf几乎可以确定不是你想要做什么。使用%f。 -
是的！就是这样！！我忘了开括号大声笑！现在我的删除功能不起作用
-
@user3739121 这将被称为“进度”。你必须真的想看它，但就是这样。如果你看得足够深入，你会在这段代码中发现很多个错误的东西。例如：
while(!feof(data))是错误的(see here for why)。main中的name分配大小不正确（基于sizeof(char*)，应该是sizeof(char)，即使这样也不是需要）。等等。有很多事情可以让你忙于解决这个问题。
标签： c struct linked-list