【发布时间】:2015-10-28 22:50:00
【问题描述】:
好的,所以我的想法是移动到循环列表中的每个节点(在这种情况下为用户)并询问他们是否要注销,他们会随机给出是或否的答案,直到每个人都登录离开。这似乎是我运行程序的大部分时间的情况,但有时用户正在重新登录,这不应该发生,我将发布我正在使用的删除方法和显示方法。
public void displayLinkedList() {
temp=first;
int i = 1;
do {
boolean rand=randomBoolean();
if(rand) {
System.out.println("USER : "+temp.data+" Logged off ");
temp.isloggedOut=true;
Node placeholder = temp.nextNode; //save value of temp.next before we delete temp
delete(temp);
Node.numOfUsers--;
temp = placeholder; //reassign "temp" to the appropriate next value.
} else if(!temp.isloggedOut) {
System.out.println("USER : "+temp.data+" Logged on ");
temp=temp.nextNode;
}
} while(Node.numOfUsers!=0);
}
public void delete(Node n) {
if(Node.numOfUsers == 0 || n == null) return; // 0 nodes or null parameter.
Node temp = first;
if(temp.nextNode == null) { //only one node
temp = null; //simply delete it
} else {
while(temp.nextNode != n) {
temp = temp.nextNode;
if(temp == first) { //if we circle the entire list and don't find n, it doesn't exist.
return;
}
}
temp.nextNode = n.nextNode; // perform the switch, deleting n
}
}
【问题讨论】:
标签: java adt nodes circular-list