【发布时间】:2019-01-03 09:09:26
【问题描述】:
我在一个返回查询组件的 Create React 应用程序中测试一个组件时遇到了一些问题,我正在使用 jest 和酶进行测试。我得到的错误是Invariant Violation: Unable to find node on an unmounted component.。我做错了什么有什么想法吗?我想要得到的是测试查询组件是否会根据从服务器接收到的数据返回一个组件数组。
我尝试使用this medium article 中发布的方法,但根本无法使用。
// The component
export class MyWrapper extends React.Component {
render() {
return (
<List divided verticalAlign="middle" >
<Query query={query} >
{({ data, loading, error, refetch }) => {
if (loading) return <Loader />;
if (error) return <ErrorMessage />;
// set refetch as a class property
this.refetch = refetch;
return data.response
.map(el => (
<MyComponent
el={el}
/>
));
}}
</Query>
</List>
);
}
}
export default compose(
...//
)(MyWrapper);
// The test file
import React from "react";
import { MockedProvider } from "react-apollo/test-utils";
import query from "path/to/query";
import { MyWrapper } from "../MyWrapper";
import { props } from "./props";
const mocks = {
request: {
query,
},
result: {
data: {
response: [
// data
]
}
}
};
describe("<MyWrapper />", () => {
describe("rendering", () => {
it("renders <MyComponent />'s", async () => {
const wrapper = mount(
<MockedProvider mocks={mocks} removeTypename>
<MyWrapper {...props} />
</MockedProvider>
);
await new Promise(resolve => setTimeout(() => resolve(), 1000));
wrapper.update();
console.log(wrapper.debug());
});
});
});
这是我试图重现的代码 sn-p:
const wait = require('waait');
it('should render dog', async () => {
const dogMock = {
request: {
query: GET_DOG_QUERY,
variables: { name: 'Buck' },
},
result: {
data: { dog: { id: 1, name: 'Buck', breed: 'poodle' } },
},
};
const component = renderer.create(
<MockedProvider mocks={[dogMock]} addTypename={false}>
<Dog name="Buck" />
</MockedProvider>,
);
await wait(0); // wait for response
const p = component.root.findByType('p');
expect(p.children).toContain('Buck is a poodle');
});
【问题讨论】:
标签: testing jestjs enzyme apollo apollo-client