【发布时间】:2015-12-09 16:42:23
【问题描述】:
我能想到的最好的解释方式是:我试图给每个机器人一个唯一的 ID。然后,当我运行该程序时,我只需要给机器人一个名称和 ID。状态是为我生成的。
但是,我遇到了一个完全障碍,因为我找不到正确的方法来做到这一点。我试过计算行数并将其放入 tempid 中。那是行不通的。每次运行时都会创建一个新行。所以,我应该总是得到一个新的身份证。不过我可能做错了。
我收到此错误:
错误(23,44):PL/SQL:ORA-00984:此处不允许列
程序如下:
CREATE OR replace PROCEDURE Checkbot
(nameinput IN VARCHAR2)
IS
partfound NUMBER(4);
foundall BOOLEAN;
tempid NUMBER;
BEGIN
--Where I am having issues:
SELECT Count(*)
INTO tempid
FROM robotinventory;
INSERT INTO robotinventory VALUES (tempid, nameinput, NULL);
foundall := TRUE;
FOR i IN 1..8 LOOP
partfound := 0;
SELECT Max(prtserial)
INTO partfound
FROM partinventory
WHERE parttypeid = i;
IF partfound > 0 THEN
DELETE FROM partinventory
WHERE prtserial = partfound;
INSERT INTO robotprt VALUES (tempid, idinput, i);
ELSE
foundall := FALSE;
END IF;
END LOOP;
IF foundall THEN
UPDATE robotinventory
SET status = 'ready for assembly'
WHERE robotid = tempid;
ELSE
UPDATE robotinventory
SET status = 'waiting on parts'
WHERE robotid = tempid;
END IF;
END;/
机器人库存表:
CREATE TABLE RobotInventory
(RobotID Number(4) PRIMARY KEY,
RobotName VARCHAR2(24),
Status VARCHAR2(64));
我的代码的以前版本,去掉了我做错的地方,我的目标是用一个自动递增的数字替换 idInput:
create or replace procedure checkbot
(idInput in number, nameInput in varchar2)
is
partFound number(4);
foundAll boolean;
begin
insert into robotInventory values (idInput, nameInput, null);
foundAll := true;
for i in 1..8 loop
partFound := 0;
select max(prtSerial)
into partFound
from partInventory
where ParttypeID = i;
if partFound > 0 then
delete from partInventory
where prtSerial = partFound;
insert into robotPrt values (partFound, idInput, i);
else
foundAll := false;
end if;
end loop;
if foundAll then
update robotInventory
set status = 'ready for assembly'
where robotID = idInput;
else
update robotInventory
set status = 'waiting on parts'
where robotID = idInput;
end if;
END;
/
【问题讨论】:
-
任何好奇的人的工作代码:pastebin.com/L5WBr4Br
标签: sql oracle primary-key increment