有趣的问题。我没有时间进行快速而肮脏的 hack,所以我们开始吧(灵感来自 mpl streamplot 中的代码)
import matplotlib.lines as mlines
import matplotlib.patches as mpatches
import matplotlib.pyplot as plt
import numpy as np
def add_arrow_to_line2D(
axes, line, arrow_locs=[0.2, 0.4, 0.6, 0.8],
arrowstyle='-|>', arrowsize=1, transform=None):
"""
Add arrows to a matplotlib.lines.Line2D at selected locations.
Parameters:
-----------
axes:
line: list of 1 Line2D obbject as returned by plot command
arrow_locs: list of locations where to insert arrows, % of total length
arrowstyle: style of the arrow
arrowsize: size of the arrow
transform: a matplotlib transform instance, default to data coordinates
Returns:
--------
arrows: list of arrows
"""
if (not(isinstance(line, list)) or not(isinstance(line[0],
mlines.Line2D))):
raise ValueError("expected a matplotlib.lines.Line2D object")
x, y = line[0].get_xdata(), line[0].get_ydata()
arrow_kw = dict(arrowstyle=arrowstyle, mutation_scale=10 * arrowsize)
if transform is None:
transform = axes.transData
arrows = []
for loc in arrow_locs:
s = np.cumsum(np.sqrt(np.diff(x) ** 2 + np.diff(y) ** 2))
n = np.searchsorted(s, s[-1] * loc)
arrow_tail = (x[n], y[n])
arrow_head = (np.mean(x[n:n + 2]), np.mean(y[n:n + 2]))
p = mpatches.FancyArrowPatch(
arrow_tail, arrow_head, transform=transform,
**arrow_kw)
axes.add_patch(p)
arrows.append(p)
return arrows
fig, ax = plt.subplots(1, 1)
t = np.linspace(0., 4*np.pi, 100.)
line = ax.plot(np.log(t+1)*np.cos(t), np.log(t+1)*np.sin(t),"-")
add_arrow_to_line2D(ax, line, arrow_locs=[0.1, 0.2, 0.3, 0.4, 0.6, 0.8, 0.99],
arrowsize=1.5)
ax.axis("equal")
ax.set_xlim([-4., 4.])
ax.set_ylim([-4., 4.])
plt.show()