在字典中查找最大的区域

Question

我正在编写一个遍历字典的函数。字典包含艺术家作为键和他们的画作为值。我需要在面积最大的字典中找到这幅画，如果有两个面积相等，则应将它们作为元组列表返回。

示例字典：

{
        'A, Jr.':[("One",1400,10,20.5,"oil paint","Austria"),("Three",1400,100.0,100.0,"oil paint","France"),("Twenty",1410,50.0,200.0,"oil paint","France")],
        'X':[("Eight",1460, 100.0, 20.0, "oil paint","France"),("Six",1465,10.0, 23.0, "oil paint", "France"),("Ten",1465,12.0,15.0,"oil paint","Austria"),("Thirty",1466,30.0,30.0,"watercolor","Germany")],   
        'M':[("One, Two", 1500, 10.0, 10.0, "panel","Germany")]
        }

基本上，四位数字是绘画或艺术作品的创作年份，接下来的两个数字是长度和宽度。在乘以长度和宽度时，我需要返回面积最大的值。所以对于上面的字典，函数 find_largest 应该返回

find_largest(dictionary2())

[('A, Jr.', 'Three'), ('A, Jr.', 'Twenty')]

由于“三”画的 100 * 100 = 10,000 和“二十”画的 50 * 200 = 10,000，它们都作为列表中的元组返回。

有人对如何做到这一点有建议吗？我已经开始了下面的代码，但我认为这不是正确的方法。

def find_largest(dictionary):
    matches = {}
    for key, the_list in db.items():
        for record in the_list:
            value = record[4]
            if dictionary in record:
                if key in matches:
                    max(the_list)
                    max(lst, key=lambda tupl: tupl[2]*tupl[3])
                    matches[key].append(record)
                else:
                    matches[key] = [record]
    return matches

这基本上是我早期函数的代码，有一些重大变化。这个基本框架已经实现了我的一些目标。我添加了 max(matches) 但我意识到这并没有做太多，除非该函数将长度和宽度相乘然后查找最大值。如果有人有建议会很有帮助

Answer 1

只跟踪当前的最大值可能会更容易

data = {
        'A, Jr.':[("One",1400,10,20.5,"oil paint","Austria"),("Three",1400,100.0,100.0,"oil paint","France"),("Twenty",1410,50.0,200.0,"oil paint","France")],
        'X':[("Eight",1460, 100.0, 20.0, "oil paint","France"),("Six",1465,10.0, 23.0, "oil paint", "France"),("Ten",1465,12.0,15.0,"oil paint","Austria"),("Thirty",1466,30.0,30.0,"watercolor","Germany")],   
        'M':[("One, Two", 1500, 10.0, 10.0, "panel","Germany")]
        }

def find_largest(d):
    matches = []
    max_value = 0
    for key in d:
        for record in d[key]:
            value = record[2] * record[3]
            if value > max_value:
                matches = [(key, record[0])]
                max_value = value
            elif value == max_value:
                matches.append((key, record[0]))
    return matches

# Output
>>> find_largest(data)
[('A, Jr.', 'Three'), ('A, Jr.', 'Twenty')]