【问题标题】:Gradient fill of geom_polygongeom_polygon 的渐变填充
【发布时间】:2013-11-14 20:18:56
【问题描述】:

此代码生成一个包含 3 个多边形的图表 ...

我正在创建一个显示 3 个多边形的图表,如果有更好的方法来绘制多边形,我不太感兴趣(实际上这些多边形代表事件并且这些事件有持续时间)。

首先,我感兴趣的是使用渐变填充每个多边形的可能性。

# library("ggplot2")
# library(data.table)

## some vectors
event.day <- c("A", "A", "B", "B")
event.time <- c(1, 2, 1, 2)
event.duration <- c(1,2,3,1)
sys <- c(100, 50, 50, 100)

## the data data.frame
df.event <- data.frame(event.day, event.time,event.duration,sys)
# ordering the data.frame
df.event <- df.event[with(df.event, order(event.day, event.time)), ]
# sys values of the next event
df.event$sys.end <- c(df.event$sys[-1], NA)
df.event$sys.min <- min(df.event$sys)
df.event$sys.minday <- ave(df.event$sys, list(event.day), FUN=function(x) {min(x)})
df.event$sys.max <- max(df.event$sys)
df.event$sys.maxday <- ave(df.event$sys, list(event.day), FUN=function(x) {max(x)})

# count all events
df.event$cntTotalNoOfEvents <- seq_along(df.event$sys)
# count the events within one day
df.event$cntTotalNoOfEventsByDay <- ave( 1:nrow(df.event), df.event$event.day,FUN=function(x)        seq_along(x))
# aggregate the number or events within one day
df.event$TotalNoOfEventsByDay <- do.call(c, lapply(df.event$event.day, function(foo){
sum(df.event$event.day==foo)
}))
# the successor event
df.event$event.successor <- c(df.event$cntTotalNoOfEvents[-1], NA)

df.event$event.day <- factor(df.event$event.day, levels = unique(df.event$event.day))
event.day.level <- levels(df.event$event.day)
df.event$event.day.level.ordinal <- as.numeric(match(df.event$event.day, event.day.level))

## the position data.frame
df.position <- data.frame(event.polygon = rep(c(1:nrow(df.event)), each = 4), polygon.x = 1,     polygon.y = 1)
df.position$event.polygon.point <- ave( 1:nrow(df.position),    df.position$event.polygon,FUN=function(x) seq_along(x))

## merge of the data and the positition data.frame
dt.polygon <- data.table(merge(df.event, df.position, by.x = "cntTotalNoOfEvents", by.y = "event.polygon"))

## calculating the points of the polygon
dt.polygon[dt.polygon$event.polygon.point == 1, polygon.x := event.day.level.ordinal - .5 *   sys / sys.max ]
dt.polygon[dt.polygon$event.polygon.point == 1, polygon.y := cntTotalNoOfEventsByDay]
dt.polygon[dt.polygon$event.polygon.point == 2, polygon.x := event.day.level.ordinal - .5 * sys.end / sys.max]
dt.polygon[dt.polygon$event.polygon.point == 2, polygon.y := cntTotalNoOfEventsByDay + event.duration]
dt.polygon[dt.polygon$event.polygon.point == 3, polygon.x := event.day.level.ordinal + .5 * sys.end / sys.max]
dt.polygon[dt.polygon$event.polygon.point == 3, polygon.y := cntTotalNoOfEventsByDay + event.duration]
dt.polygon[dt.polygon$event.polygon.point == 4, polygon.x := event.day.level.ordinal + .5 * sys / sys.max]
dt.polygon[dt.polygon$event.polygon.point == 4, polygon.y := cntTotalNoOfEventsByDay]

p <- ggplot()

p <- p +    geom_polygon(data = dt.polygon
        ,aes(
            x = polygon.x
            ,y = polygon.y
            ,fill = sys
            ,group = cntTotalNoOfEvents
        )
    )

p <- p + theme(
panel.background = element_rect(fill="white")
)

p <- p + scale_fill_gradient(guide = "colourbar", low = "lightgrey",  high = "red")

p <- p +    coord_flip()

p

制作这张图表

我想要达到的目标是这样的

,你有什么想法

一如既往地感谢任何提示

汤姆

【问题讨论】:

    标签: r ggplot2


    【解决方案1】:

    嗯,其实我不确定回答我自己的问题是否有意义......

    但由于我没有收到任何答案,可能我最初的问题有点愚蠢。

    不过,在最后一天我花了一些时间来解决我的问题。基本上我的解决方案是根据事件的持续时间添加额外的段。在此期间,我省去了我的计算。这是因为我最初的兴趣是如何为多边形提供渐变。

    也许你们中的一些人觉得我的解决方案很有用

    汤姆干杯

    library(ggplot2)
    library(reshape)
    event.day <- c("A", "A", "A", "A", "B", "B")
    event <- c(1, 2, 3, 4, 5, 6)
    sys <- c(120, 160, 100, 180, 100, 180)
    duration <- c(50, 100, 50, 150, 350, 0)
    df <- data.frame(event.day, event, sys, duration)
    df$end <- c(df$sys[-1], NA)
    
    ## replacing na values
    df.value.na <- is.na(df$end)
    df[df.value.na,]$end <- df[df.value.na,]$sys
    
    ## calculating the slope
    df$slope <- df$end / df$sys
    
    ## creating rows for each event depending on the duration
    event.id <- vector()
    segment.id <- vector()
    
    for(i in 1:nrow(df)) {
    event.id <- c(event.id, rep(df[i,]$event, each = df[i,]$duration))
    segment.id <- c(segment.id,c(1:df[i,]$duration))
    }
    
    ## merging the original dataframe with the additional segments
    df.segments <- data.frame(event.id, segment.id) 
    df <- merge(df, df.segments, by.x = c("event"), by.y = c("event.id"))
    
    ## calculate the start and end values for the newly created segements
    df$segment.start <- df$sys + (df$segment.id - 1) * (df$end - df$sys) / df$duration
    df$segment.end <- df$sys + (df$segment.id) * (df$end - df$sys) / df$duration
    
    ## just a simple calculation
    value.max <- max(df$sys)
    
    df$high <- 1 + 0.45 * df$segment.end / value.max
    df$low <- 1 - 0.45 * df$segment.end / value.max
    df$percent <- df$segment.end / value.max 
    df$id <- seq_along(df$sys)
    df$idByDay <- ave( 1:nrow(df), df$event.day,FUN=function(x) seq_along(x))
    
    
    ## how many events in total, necessary
    newevents <- nrow(df)
    
    ## subsetting the original data.frame
    df <- df[,c("event.day", "id", "idByDay", "segment.id", "segment.start", "duration", "segment.end", "high", "low", "percent")]
    
    ## melting the data.frame
    df.melted <- melt(df, id.vars = c("event.day", "id", "idByDay", "segment.id", "segment.start", "duration", "segment.end","percent"))
    df.melted <- df.melted[order(df.melted$id,df.melted$segment.id),]
    
    ## this is a tricky one, basically this a self join, of two tables
    #  every event is available twice, this is due to melt in the previous section
    #  a dataframe is produced where every event is contained 4 times, except the first and last 2 rows,
    #  the first row marks the start of the first polygon
    #  the last row marks the end of the last polygon
    df.melted <- rbind(df.melted[1:(nrow(df.melted)-2),],df.melted[3:nrow(df.melted),])
    df.melted <- df.melted[order(df.melted$id,df.melted$segment.id),]
    
    
    ## grouping, necessary for drawing the polygons
    #  the 1st polygon spans from the 1st event, and the first 2 rows from 2nd event
    #  the 2nd polygon spans from last 2 rows of the 2nd event and the first 2 rows from 3rd event
    #  ...
    #  the last polygon spans from the last 2 rows of the next to last event and the 2 rows of the last event
    df.melted$grouping <- rep (1:(newevents-1), each=4)
    df.melted <- df.melted[order(df.melted$id, df.melted$grouping, df.melted$variable), ]
    
    
    ## adding a 4 point for each group
    df.melted$point <- rep(c(1,2,4,3),(newevents-1))
    df.melted <- df.melted[order(df.melted$grouping,df.melted$point), ]
    
    ## drawing the polygons
    p <-        ggplot()
    
    p <- p +    geom_polygon(data = df.melted
                ,aes(
                    x = value
                    ,y =idByDay
                    ,group = grouping
                    ,fill = percent
    
                )
            ) 
    
    p <- p +    labs(x = "something", y="something else")
    
    p <- p +    theme(
                    panel.background = element_blank()
                    #,panel.grid.minor = element_blank()
                #axis.title.x=element_blank()
                    #,axis.text.x=element_text(size=12, face=2, color="darkgrey")
                    #,axis.title.y=element_blank()
                #,axis.ticks.y = element_blank()
                    #,axis.text.y = element_blank()
    )
    
    p <- p +    scale_fill_gradient(
                low = "lightgrey"
                ,high = "red"
                ,guide = 
                    guide_legend(
                        title = "Sys" 
                        ,order = 1
                        ,reverse = FALSE
                        ,ncol = 2
                        ,override.aes = list(alpha = NA)
                    )
            )
    
    p <- p +    facet_wrap(~event.day, ncol=2)
    
    p
    

    使用此代码,我能够创建一个如下所示的图表:

    【讨论】:

    • 仅使用向量优化了 data.frame 上的循环,而没有关于持续时间的第二个循环
    • 回答您自己的问题是strongly encouraged。感谢您分享您学到的知识!
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