这就是你的做法。下一个代码是使用 Visual Studio 2010 C++ 控制台项目编写的。首先是汇编部分,注意cmets,如何从栈中获取字符串的地址,如何访问字符,最重要的部分,如何删除不需要的字符:
.386
.model flat, C
.code
;-------------------------------------------------------
check_alphanum proc
;PRESERVE EBP, ESI.
push ebp
push esi
mov ebp, esp
add ebp, 12 ;GET PARAMETER'S ADDRESS.
mov esi, [ ebp ] ;ESI POINTS TO ARRAY.
whil:
mov al, [ esi ] ;GET CURRENT CHAR.
cmp al, 0 ;CHECK END OF ARRAY.
je finale ;IF ( AL == 0 ) END OF STRING.
;CHECK IF CURRENT CHAR IS 0..9-A..Z-a..z.
cmp al, '0'
jb its_invalid ;IF ( AL < '0' ) INVALID.
cmp al, '9'
jbe its_valid ;IF ( AL <= '9' ) VALID.
cmp al, 'A'
jb its_invalid ;IF ( AL < 'A' ) INVALID.
cmp al, 'Z'
jbe its_valid ;IF ( AL <= 'Z' ) VALID.
cmp al, 'a'
jb its_invalid ;IF ( AL < 'a' ) INVALID.
cmp al, 'z'
jbe its_valid ;IF ( AL <= 'z' ) VALID.
jmp its_invalid ;INVALID BECAUSE AL > 'z'.
its_valid:
;NEXT CHAR TO PROCESS.
inc esi
jmp whil
its_invalid:
;DELETE CURRENT CHAR PUSHING ALL CHARS ONE PLACE TO THE LEFT.
mov edi, esi ;EDI POINTS TO CURRENT CHAR TO DELETE.
mov ebx, esi ;EBX ALSO POINTS TO CURRENT CHAR.
inc ebx ;NOW EBX POINTS TO NEXT CHAR.
shifting_left:
mov al, [ ebx ] ;AL = NEXT CHAR.
mov [ edi ], al ;CURRENT CHAR REPLACED BY NEXT.
cmp al, 0
je end_shifting
inc edi
inc ebx
jmp shifting_left
end_shifting:
jmp whil ;REPEAT PROCESS FOR NEXT CHAR.
finale:
;RESTORE EBP, ESI.
pop esi
pop ebp
ret
check_alphanum endp
;-------------------------------------------------------
end
现在是 C++ 部分。以前的过程可以这样调用,例如,从“main”方法中调用:
extern "C" void check_alphanum ( char * arr );
...
char arr[] = "A213457B-3746DFA3-578EC20E-4567DFF2-08A1B3AC-7B125F3A";
check_alphanum( arr );
得到的字符串是:
"A213457B3746DFA3578EC20E4567DFF208A1B3AC7B125F3A"
下一张图片显示了项目树中外部程序集文件的位置:
您所要做的就是向您的项目添加一个新文件,随意命名,但使用“.asm”扩展名,将我的代码复制粘贴到其中,就可以使用(或准备好)打电话)。