将代码转换为数组并显示

Question

我怎样才能把它变成一个数组？我需要一块板来显示空白，当用户输入时，它会被另一个函数填充为 X 或 O。当前板子工作我想把它做成一个数组[3][3]并显示数组的内容。

void showboard(char &squareOne, char &squareTwo, char &squareThree, char &squareFour, char &squareFive, char &squareSix, char &squareSeven,
    char &squareEight, char &squareNine)
{


 cout << squareOne << "|" << squareTwo << "|" << squareThree << endl
  << "-+-+-"<< endl
  << squareFour << "|" << squareFive << "|" << squareSix << endl
  << "-+-+-"<< endl
  << squareSeven << "|" << squareEight << "|" << squareNine << endl;
 }
}

Answer 1

您可以让showboard() 函数接受对chars 的3x3 数组的引用。看起来很奇怪的参数char (&squares)[3][3] 表示“引用名为squares 的chars 的3x3 数组”。

void showboard(char (&squares)[3][3]) 
{ 
    std::cout << squares[0][0] << "|" << squares[0][1] << "|"
         << squares[0][2] << "\n" << "-+-+-"<< "\n" 
         << squares[1][0] << "|" << squares[1][1] << "|"
         << squares[1][2] << "\n" << "-+-+-"<< "\n"
         << squares[2][0] << "|" << squares[2][1] << "|"
         << squares[2][2] << std::endl; 
} 

int main()
{
    char s[3][3] = { {'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'} };
    showboard(s);
}

或者，这是一个使用 for 循环的实现：

void showboard(char (&squares)[3][3]) 
{ 
    for(int i = 0; i < 3; ++i)
    {
        for(int j = 0; j < 3; ++j)
        {
            std::cout << squares[i][j];
            if(j < 2) std::cout << "|";
        }
        std::cout << "\n";
        if(i < 2) std::cout << "-+-+-" << std::endl;;
    }
} 

Answer 2

template <typename T, int nRows, int nCols>
class Matrix: public vector<vector<T>>
{
public:
    Matrix()
    {
        for (int r = 0; r < nRows; ++r)
        {
            vector<T> row;
            row.resize(nCols);
            fill(row.begin(), row.end(), 0);
            this->push_back(row);
        }
    }

    int rows() const { return nRows; }
    int columns() const { return nCols; }
};

typedef Matrix<int, 3, 3> Board;

void show(const Board& board)
{
    for (int i = 0; i < board.rows(); ++i)
    {
        for (int j = 0; j < board.columns(); ++j)
            cout << board[i][j] << " ";
        cout << endl;
    }
}