【发布时间】:2020-12-28 14:45:26
【问题描述】:
-
这是代码
-
并且无法识别错误
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它将
new_content显示为错误。我更改了它的名称,但也显示错误
我认为这是一个逻辑错误
module IF_ID(new_content, instruction, newPC, clk, pwrite1);
input pwrite1, clk;
input [31:0] instruction, newPC;
output [63:0] new_content;
reg [63:0] next;
always (@negedge clk) begin
if(pwrite1)
new_content <= {instruction, newPC};
else
new_content <= 64'b0;
end
endmodule
我收到以下错误:
jdoodle.v:6: syntax error
jdoodle.v:8: Syntax in assignment statement l-value.
jdoodle.v:9: syntax error
jdoodle.v:10: error: invalid module item.
jdoodle.v:12: syntax error
【问题讨论】:
标签: verilog system-verilog iverilog