比较三个哈希数组并在 ruby​​ 中得到没有重复的结果？

Question

我正在使用fql gem 从 facebook 检索数据。原始的哈希数组是这样的。 Here。当我比较这三个哈希数组时，我想以这种方式获得最终结果：

{
      "photo" => [
        [0] {
                   "owner" : "1105762436",
                 "src_big" : "https://fbcdn-sphotos-b-a.akamaihd.net/hphotos-ak-xap1/t31.0-8/q71/s720x720/10273283_10203050474118531_5420466436365792507_o.jpg",
                 "caption" : "Rings...!!\n\nView Full Screen.",
                 "created" : 1398953040,
                "modified" : 1398953354,
               "like_info" : {
                  "can_like" : true,
                "like_count" : 22,
                "user_likes" : true
            },
            "comment_info" : {
                  "can_comment" : true,
                "comment_count" : 2,
                "comment_order" : "chronological"
            },
               "object_id" : "10203050474118531",
                     "pid" : "4749213500839034982"
        }
    ],
    "comment" => [
        [0] {
                 "text" : "Wow",
            "text_tags" : [],
                 "time" : 1398972853,
                "likes" : 1,
               "fromid" : "100001012753267",
            "object_id" : "10203050474118531"
        },
        [1] {
                 "text" : "Woww..",
            "text_tags" : [],
                 "time" : 1399059923,
                "likes" : 0,
               "fromid" : "100003167704574",
            "object_id" : "10203050474118531"
        }
    ],
     "users" =>[
         [0] {
                  "id": "1105762436",
                "name": "Nilanjan Joshi",
            "username": "NilaNJan219"
         },
         [1] {
                  "id": "1105762436",
                "name": "Ashish Joshi",
            "username": "NilaNJan219"
         }
    ]
}

这是我的尝试：

datas = File.read('source2.json')
all_data = JSON.parse(datas)
photos = all_data[0]['fql_result_set'].group_by{|x| x['object_id']}.to_a 
comments = all_data[1]['fql_result_set'].group_by{|x| x['object_id']}.to_a 
@photos_comments = []
@comments_users = []
@photo_users = []
photos.each do |a|
 comments.each do |b|
   if a.first == b.first
    @photos_comments << {'photo' => a.last, 'comment' => b.last}   
   else
    @comments_users << {'photo' => a.last, 'comment' => ''} unless @photos_comments.include? (a.last)
   end
 end
end

@photo_users = @photos_comments | @comments_users
@photo_comment_users = {photos_comments: @photo_users }

这是我得到的final result

最终数组中仍然存在重复项。我有grouped byobject id 的数组，这在照片和评论数组之间很常见。但问题在于只拍摄那些有 cmets 的照片。我不知道如何找出没有 cmets 的照片。 另外为了找出评论者的详细信息，ive users 数组，comments 和users 之间的共同属性是fromid 和id。我也无法理解如何获取用户详细信息。

Answer 1

我想这就是你想要的：

photos = all_data[0]['fql_result_set']
comments = all_data[1]['fql_result_set'].group_by{|x| x['object_id']}
@photo_comment_users = photos.map do |p| 
  { 'photo' => p, 'comment' => comments[p['object_id']] || '' }
end

对于每个photo，它需要所有具有相同object_id 的comments，或者如果不存在，则返回''。

---

如果你也想连接用户，可以通过id映射，通过评论选择相关的：

users = Hash[all_data[2]['fql_result_set'].map {|x| [x['id'], x]}]
@photo_comment_users = photos.map do |p| 
  { 'photo' => p, 'comment' => comments[p['object_id']] || '', 
    'user' => (comments[p['object_id']] || []).map {|c| users[c['formid']]} }
end