如何从给定数据中获取任何 url答案

【问题标题】：How to get any url from the given data如何从给定数据中获取任何 url
【发布时间】：2026-01-26 06:45:02
【问题描述】：

我想从给定的数据中获取 url。

例如我有一个变量中的数据

$data = "is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, http://www.youtube.com/watch?v=mm78xlsADgc when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but";

现在我想从给定的变量$data 中获取这个 URL (http://www.youtube.com/watch?v=mm78xlsADgc)。请告诉我该怎么做？

【问题讨论】：

你在这个网站上搜索过吗？
是的，我在网站上搜索过，但没有得到解决方案，这就是我发布此问题的原因。
您可以尝试查找 URL 验证正则表达式，例如*.com/questions/206059/php-validation-regex-for-url/…
这是否从 $data 变量返回 url？我认为它将验证该字符串是否为 url。我说的对吗？
我设法链接到该问题中的错误答案。我的意图是链接到使用正则表达式的已接受答案。在您的情况下，您将无法使用 filter_var，但您可以对 URL 进行模式匹配。

标签： php preg-match preg-match-all preg-split

【解决方案1】：

您应该filter_var() 这样做。

var_dump(filter_var('http://www.youtube.com/watch?v=', FILTER_VALIDATE_URL));

【讨论】：

这会返回 $data 变量中的 url 吗？
不，它没有。 OP 希望在字符串中查找 URL，而不是验证字符串是否为 URL。

【解决方案2】：

使用上面的this answer 和您的$data 中的模式：

preg_match_all(
    '#((?:http|https|ftp)://(?:\S*?\.\S*?))(?:\s|\;|\)|\]|\[|\{|\}|,|"|\'|:|\<|$|\.\s)#i',
    $data,
    $matches
);
var_dump($matches[1]);

See it in action on Ideone.

根据您要匹配的 URL 类型，您可能希望使用实际使用的模式，但概念是相同的。

【讨论】：

【解决方案3】：

试试这个

$data = "is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, http://www.youtube.com/watch?v=mm78xlsADgc when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but";
$array1 = explode(" ", $data);
$searchword = 'http';
$matches = array();
foreach($array1 as $k=>$v) {
    if(preg_match("/\b$searchword\b/i", $v)) {
       echo $matches[$k] = $v;
    }
}

【讨论】：

【解决方案4】：

怎么样：

preg_match_all(
    '#(https?://(?:\S+))#i',
    $data,
    $matches
);

\S 代表任何不是空格的字符。

【讨论】：

【解决方案5】：

<?php  
$data = "is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, http://www.youtube.com/watch?v=mm78xlsADgc when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but";

preg_match('/(https?:.*?)\s+/si', $data, $url);

echo $url[0];
?>

DEMO

【讨论】：

【解决方案6】：

使用此代码，它对我很有效

$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";

// The Text you want to filter for urls
$text = "is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, http://www.youtube.com/watch?v=mm78xlsADgc when an unknown printer took a galley of type and scrambled it to make a type   specimen book. It has survived not only five centuries, but";

// Check if there is a url in the text
if(preg_match($reg_exUrl, $text, $url)) {


       return preg_replace($reg_exUrl, $url[0], $text);

} 

}

【讨论】：