Swift - 连接循环数组答案

【问题标题】：Swift - Concatenate Looped ArraysSwift - 连接循环数组
【发布时间】：2015-09-04 07:07:12
【问题描述】：

我只是想知道是否可以连接循环数组并将其附加到单个字符串中？示例：

var name = ["John","Peter","Damian"] 
var age = ["23","21","25"] 
var occupation = ["Plumber","Carpenter","Painter"]

var names = String()
var ages = String()
var occu = String()
var output = String()

    for var i = 0; i < name.count; i++ {
           names = name[i]
           ages = age[i]
           occu = occupation[i]
}
output = String(format:"%@ is %@Years Old, He's a %@.",names,ages,occu)
println(output) //Damian is 25Years Old, He's a Painter.

如果我想在一个字符串中输出所有数组，用“，”或“And”分隔，例如：Damian is 25 Years Old, He's a Painter AND John is 23....... AND Peter is......... 非常感谢！

【问题讨论】：

标签： arrays swift for-loop

【解决方案1】：

这样你就可以做到：

var name = ["John","Peter","Damian"]
var age = ["23","21","25"]
var occupation = ["Plumber","Carpenter","Painter"]

var names = String()
var ages = String()
var occu = String()
var output = String()
var finalArr = [String]()

for var i = 0; i < name.count; i++ {

    names = name[i]
    ages = age[i]
    occu = occupation[i]
    output = "\(names) is \(ages) Years Old, He's a \(occu)."
    finalArr.append(output)   //append every sentence into finalArr

}
let stringRepresentation = " And ".join(finalArr) // convert finalArr to string.

输出：

John is 23 Years Old, He's a Plumber. And Peter is 21 Years Old, He's a Carpenter. And Damian is 25 Years Old, He's a Painter.

【讨论】：

【解决方案2】：

Swift1.2：

var name = ["John","Peter","Damian"]
var age = ["23","21","25"]
var occupation = ["Plumber","Carpenter","Painter"]


let output = " AND ".join(
    map(indices(name), {
        "\(name[$0]) is \(age[$0]) Years Old, He's a \(occupation[$0])"
    })
) + "."

println(output)

// John is 23 Years Old, He's a Plumber AND Peter is 21 Years Old, He's a Carpenter AND Damian is 25 Years Old, He's a Painter.

Swift2：

var name = ["John","Peter","Damian"]
var age = ["23","21","25"]
var occupation = ["Plumber","Carpenter","Painter"]

let output = name.indices.map({
    "\(name[$0]) is \(age[$0]) Years Old, He's a \(occupation[$0])"
}).joinWithSeparator(" AND ") + "."

print(output)

【讨论】：