无法从 json 数组中删除正确的对象

Question

这是我拥有的 json 结构...

{
  "comment": "Test123",
  "scheduleId": "291701",
  "observations": [
    {
      "typeId": 1,
      "comment": "Test",
      "categoryId": 852,
      "smateeId": 217094,
      "subCategoryId": 5726,
      "hasImage": false
    },
    {
      "typeId": 2,
      "categoryId": 861,
      "comment": "Hshh",
      "subCategoryId": 5825,
      "smateeId": 217094,
      "hasImage": false
    },
    {
      "subCategoryId": 5908,
      "smateeId": 217094,
      "typeId": 3,
      "comment": "Hehh",
      "categoryId": 870,
      "hasImage": false
    }
  ],
  "schedule": {
    "smatorIds": [
      19369,
      19370
    ],
    "workstationId": "196890",
     "plant": {
      "id": "2980",
      "gaiaCode": "k987976",
      "name": "ASDHKJK/ASDA"
    },
    "departmentId": "188848"
  },
  "shiftId": null
}

现在我想要实现的是从observations 数组中删除一个特定元素。在observations 数组中，键typeId、categoryId、smateeId、subCategoryId 不是唯一的。所以为了有一个唯一的值来识别每个对象，我像这样在字典中添加了一个随机数......

ArrayData.shared.obsIndex = Int.random(in: 0 ..< 10000)

    positiveObservationDict["smateeId"] = ArrayData.shared.smatReceiverIDArray1[0]
    positiveObservationDict["categoryId"] = Int(self.Category_Id)

    positiveObservationDict["typeId"] = 1
    positiveObservationDict["subCategoryId"] = Int(self.Sub_Category_Id)
    positiveObservationDict["comment"] = self.PO_Comments.text!

    positiveObservationDict["hasImage"] = false
    positiveObservationDict["tempID"] = ArrayData.shared.obsIndex

ArrayData.shared.arrayOfObservations.append(positiveObservationDict)

现在我将另一个字典两次放入同一个数组中......（我再次将一个随机数也添加到该字典中）

ArrayData.shared.obsIndex = Int.random(in: 0 ..< 10000)

    newDict["smateeId"] = ArrayData.shared.smatReceiverIDArray1[0]
    newDict["categoryId"] = Int(self.Category_Id)

    newDict["typeId"] = 1
    newDict["subCategoryId"] = Int(self.Sub_Category_Id)
    newDict["comment"] = self.PO_Comments.text!

    newDict["hasImage"] = false
    newDict["tempID"] = ArrayData.shared.obsIndex

ArrayData.shared.arrayOfObservations.append(newDict)

所以我添加随机数后的新json结构是这样的……

{
  "comment": "Test123",
  "scheduleId": "291701",
  "observations": [
    {
      "typeId": 1,
      "comment": "Test",
      "categoryId": 852,
      "smateeId": 217094,
      "subCategoryId": 5726,
      "hasImage": false
      “tempID”: 2563    
    },
    {
      "typeId": 2,
      "categoryId": 861,
      "comment": "Hshh",
      "subCategoryId": 5825,
      "smateeId": 217094,
      "hasImage": false
      “tempID”: 765
    },
    {
      "subCategoryId": 5908,
      "smateeId": 217094,
      "typeId": 3,
      "comment": "Hehh",
      "categoryId": 870,
      "hasImage": false
      “tempID”: 174
    }
  ],
  "schedule": {
    "smatorIds": [
      19369,
      19370
    ],
    "workstationId": "196890",
     "plant": {
      "id": "2980",
      "gaiaCode": "k987976",
      "name": "ASDHKJK/ASDA"
    },
    "departmentId": "188848"
  },
  "shiftId": null
}

现在我想用tempID 765 删除对象。这就是我正在做的事情......

 let index = ArrayData.shared.arrayOfObservations.index(where: { dictionary in
      guard let value = dictionary["tempID"] as? Int
        else { return false }
      return value == ArrayData.shared.obsIndex
    })
    if let index = index {
        ArrayData.shared.arrayOfObservations.remove(at: index)
    }

但是通过这样做，被删除的对象是带有tempID 2563 的对象，而不是带有tempID 765 的对象。我怎样才能删除正确的对象..？

编辑：另外，在return value == ArrayData.shared.obsIndex 上面的这个地方，我也不能在return value == 765 上做这样的事情。我想传递确切的值...

Answer 1

首先，您需要知道要删除哪些数据的正确信息。您不必拥有唯一的 id 来删除数据。

考虑以下数据

"observations": [
        {
          "typeId": 1,
          "comment": "Test",
          "categoryId": 852,
          "smateeId": 217094,
          "subCategoryId": 5726,
          "hasImage": false
        },
        {
          "typeId": 2,
          "categoryId": 861,
          "comment": "Hshh",
          "subCategoryId": 5825,
          "smateeId": 217094,
          "hasImage": false
        }]

let observations = [Observation]()
let data = observations.filter({$0.typeId != 1})

此数据将只有“typeId = 2”数据。如果您有多个“typeId = 1”的数据，则所有“typeId = 1”的数据将被删除，其他typeId值将被保留。

Answer 2

语法更简单

let objectID = 765
if let index = ArrayData.shared.arrayOfObservations.firstIndex(where: { $0["tempID"] as? Int == objectID}) {
    ArrayData.shared.arrayOfObservations.remove(at: index)
}

或者写一个函数

func deleteObject(withID objectID : Int) {
    if let index = ArrayData.shared.arrayOfObservations.firstIndex(where: { $0["tempID"] as? Int == objectID}) {
        ArrayData.shared.arrayOfObservations.remove(at: index)
    }
}

然后调用它

deleteObject(withID: 765)