程序一直打印一个零字节？

Question

我正在尝试创建一个从句子中删除元音的程序。但是，我的程序一直失败，因为它一直在字符串中打印零字节。谁能告诉我我哪里出错了？

#include <stdio.h>

int remove_all_vowels(int character);

int main(void) {

int character = getchar();
while (character != EOF && character != '\0') {

int new_character = remove_all_vowels(character);
putchar(new_character);

character = getchar();
}


return 0;

}

int remove_all_vowels(int character) {
if (character == 'a' || character == 'e' || character == 'i' || character 
== 'o' || character == 'u') {
return 0;
} else {
return character;
}

}

Answer 1

您的问题（输出空字符）来自于您无条件地 putchar(3) remove_all_vowels 的结果，当给定字符是元音时，它返回 0（空字符）。

用空格替换元音：

您可以简单地将 remove_all_vowels 中的 return 0; 更改为 return ' ';

彻底删除元音：

我建议使用一个函数来帮助您检查元音，而不是让它像一个字符的转换一样，这真的是最pythonest。

代码示例：

int is_vowel(int character) {
    return (
           character == 'a' || character == 'e' || character == 'i'
        || character == 'o' || character == 'u'
    );
}

// Then, in your main...
...
if (!is_vowel(character))
    putchar(character);

Answer 2

您的程序在这里运行良好 https://www.onlinegdb.com/online_c_compiler

可以截图你的编译器有什么问题吗？

    #include <stdio.h>
#include <string.h>

int check_vowel(char);

int main()
{
  char s[100], t[100];
  int c, d = 0;

  printf("Enter a string to delete vowels\n");
  gets(s);

  for(c = 0; s[c] != '\0'; c++) {
    if(check_vowel(s[c]) == 0) {       // If not a vowel
      t[d] = s[c];
      d++;
    }
  }

  t[d] = '\0';

  strcpy(s, t);  // We are changing initial string. This is optional.

  printf("String after deleting vowels: %s\n", s);

  return 0;
}

int check_vowel(char ch)
{
    if (ch == 'a' || ch == 'A' || ch == 'e' || ch == 'E' || ch == 'i' || ch == 'I' || ch =='o' || ch=='O' || ch == 'u' || ch == 'U')
      return 1;
    else
      return 0;
}