无法解决这个问题，更新java中的数组

Question

我即将完成一个基于文本的 Java 棋盘游戏（非常基础）。我被困在最后一件事上 -

基本上，当用户使用“roll”类型来掷虚拟骰子时会发生这种情况。然后根据结果更新数组以更改 'o' 的位置（这使得计数器看起来像已移动）。我已经想出了如何为第一卷制作这个。

但我不知道如何使第二卷和第一卷相加（以此类推，第三和第四卷）。

（示例 -

掷骰子 1：玩家掷骰子 - 得到 3 - 移动到棋盘上的第三个位置（已解决）

掷出 2：游戏记住最后掷出的是 3 - 玩家掷出 4 - 更新棋盘并将计数器移至数字 7）

这里是相关代码的sn-p：

    public void play(String p1Name2, String p2Name2){

    Scanner user_input = new Scanner(System.in);
    Random rn = new Random();
    String p1Roll = null,p2Roll;
    int[] p1r = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30};

    int b= 0,c= 0,d = 0,e = 0,g = 0;

    while(array1[10] != 'o'){
        c++;

            if(b==0) {
                int i =1;
                System.out.println("Player 1, type roll to roll the die. ");
                p1Roll = user_input.next();

                    if(p1Roll.equalsIgnoreCase("roll")){
                        p1r[c] = rn.nextInt(6);
                        p1r[c] += 1;
                        System.out.println("You rolled a: " + p1r[c]);


                        for(int f = 0; f< 10; f++ ){
                            if(array1[f] == 'o'){
                              array1[f] = 'x';
                              array1[p1r[c]] = 'o';
                              if(i ==1){
                                  this.board();
                                  i = 0;

                            }
                        }                       
                }
            }


            if(b==1) {      

            }

    }   
    }
}

和

    public void board(){


    System.out.println("           1  2  3  4  (5)  6  7  8  9  10  11");
    System.out.println("Player 1:  " + array1[0]+ "  " + array1[1] + "  " + array1[2]+ "  " + array1[3] + "   " + array1[4]+ "   " + array1[5] + "  " + array1[6]+ "  " + array1[7] + "  " + array1[8]+ "  " + array1[9] + "   " + array1[10]);
    System.out.println("Player 2:  " + array2[0]+ "  " + array2[1] + "  " + array2[2]+ "  " + array2[3] + "   " + array2[4]+ "   " + array2[5] + "  " + array2[6]+ "  " + array2[7] + "  " + array2[8]+ "  " + array2[9] + "   " + array2[10]);


}

最后，这是控制台输出：

Player 1, type roll to roll the die. 
roll
You rolled a: 4
           1  2  3  4  (5)  6  7  8  9  10  11
Player 1:  x  x  x  x   o   x  x  x  x  x   x
Player 2:  o  x  x  x   x   x  x  x  x  x   x
Player 1, type roll to roll the die. 
roll
You rolled a: 4
           1  2  3  4  (5)  6  7  8  9  10  11
Player 1:  x  x  x  x   o   x  x  x  x  x   x
Player 2:  o  x  x  x   x   x  x  x  x  x   x
Player 1, type roll to roll the die. 
roll
You rolled a: 2
           1  2  3  4  (5)  6  7  8  9  10  11
Player 1:  x  x  o  x   x   x  x  x  x  x   x
Player 2:  o  x  x  x   x   x  x  x  x  x   x
Player 1, type roll to roll the die.

Answer 1

您可以按如下方式更改代码：

public void play(String p1Name2, String p2Name2){

    Scanner user_input = new Scanner(System.in);
    Random rn = new Random();
    String p1Roll = null,p2Roll;
    int[] p1r = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30};

    int b= 0,c= 0,d = 0,e = 0,g = 0;

    while(array1[10] != 'o'){
        c++;
        if(b==0) {
            int i =1;
            System.out.println("Player 1, type roll to roll the die. ");
            p1Roll = user_input.next();

                if(p1Roll.equalsIgnoreCase("roll")){
                    p1r[c] = rn.nextInt(6);
                    p1r[c] += 1;
                    System.out.println("You rolled a: " + p1r[c]);


                    for(int f = 0; f< 10; f++ ){
                        if(array1[f] == 'o'){
                          array1[f] = 'x';
                          /** Update Current Position **/
                          array1[p1r[f] + p1r[c]] = 'o';
                          if(i == 1){
                              this.board();
                              i = 0;
                          }
                          break;
                        }                       
                    }
                }
            }   
       }
   }

但是，请注意，您目前正冒着在array[p1r[c]] 以及更新版本中获取 ArrayIndexOutOfBoundException 的风险。因此，我建议您解决这个问题，例如使用模块化访问 array[(p1r[c%p1r.length]%array.length)]。这取决于您希望在这种情况下的游戏行为。

希望对你有帮助！

Answer 2

你问我它在物体中的样子。它看起来像这样：

该小组拥有所有玩家。
玩家有一个棋盘。
棋盘跟踪每个玩家的位置。

import java.util.*;
import java.lang.*;
import java.io.*;


class Game
{
    public static void main (String[] args) throws java.lang.Exception
    {
        Group group = new Group();
        group.createPlayer("Michael");
        group.createPlayer("Jeff");
        group.createPlayer("Fred"); 
        group.renderBoard();
        int round = 1;
        while(true) {
            System.out.println("Game round "+round);
            round++;
            group.getInputs();
            group.renderBoard();
            if(group.isGameFinished()) {
                Player winner = group.getWinner();
                System.out.println("Player "+winner.getName() + " is the winner! Congratulations");
                break;
            }

        }
    }

}
class Group {
    private ArrayList<Player> group;
    public Group() {
        this.group =  new ArrayList<Player>();
    }
    public void createPlayer(String name) {
        this.group.add(new Player(name));
    }
    public void renderBoard() {
        Iterator<Player> it = this.group.iterator();
        while(it.hasNext()) {
            Player current = it.next();
            current.renderBoard();
        }
    }
    public void getInputs() {
        Iterator<Player> it = this.group.iterator();
        while(it.hasNext()) {
            Player currentMove = it.next();
            currentMove.getDiceRoll();
        }
    }
    public boolean isGameFinished() {
        Iterator<Player> it = this.group.iterator();
        while(it.hasNext()) {
            Player currentMove = it.next();
            if(currentMove.isFinished()) {
                return true;
            }
        }
        return false;
    }
    public Player getWinner() {
        Iterator<Player> it = this.group.iterator();
        while(it.hasNext()) {
            Player currentMove = it.next();
            if(currentMove.isFinished()) {
                return currentMove;
            }
        }
        return new Player("Nobody");
    }
}
class Player {
        private Scanner user_input;
        private Random rn;
        private String name;
        private Board board;
        public Player(String name) {
            this.name = name;
            this.user_input = new Scanner(System.in);
            this.rn = new Random();
            this.board = new Board(11);
        }
        public void getDiceRoll() {
            System.out.println("Player "+this.name+", type roll to roll the die. ");
            String input = user_input.next();
            if(input.equalsIgnoreCase("roll")) {
                int dieRoll = rn.nextInt(6);
                System.out.println("You rolled a "+dieRoll+"!");
                this.board.updateLocation(dieRoll);
            }
        }
        public String getName() {
            return this.name;
        }
        public boolean isFinished() {
            return this.board.isFinished();
        }
        public void renderBoard() {
            System.out.println(this.name +" > "+this.board.renderBoard());
        }
    }
    class Board {
        private int size;
        private int location;
        public Board(int size) {
             this.size = size;
             this.location = size;
        }
        public void reset() {
            this.location = this.size;
        }
        public boolean isFinished() {
            return this.location <= 0;
        }
        public void updateLocation(int amount) {
            this.location -= amount;
            if(this.location < 0) {
                this.location = 0;
            }
        }
        public String renderBoard() {
            StringBuilder builder = new StringBuilder();
            for(int c=0;c<=this.size;c++) {
                if(c == this.location) {
                    builder.append('o');
                }
                else {
                    builder.append('x');
                }
                builder.append(' ');
            }
            return builder.toString();
        }
    }