如何在字符串中找到某些单词？

Question

我有一个字符串数组，每个字符串都包含一个关键字和一个数字（数值不同，只有关键字是常数），我想知道如何获取单词和数字.. .看下面的例子：

var keyWords = ["data","action","type"];

var stringArray = ["set data4 to custom value '1'",
                   "set data110 to custom value '2'",
                   "overwrite value of action1023 with new value",
                   "set type23 to custom value '10'",
                   "overwrite value of action13 with text",
                   "set type48 to custom value '7'"]

响应应该是这样的：

var response = ["data4","data110","action13","type23","action1023","type48"];

这是我设法做到的：

  var response = [];
  for(var j=0; j<keyWords.length; j++) {
    for(var i=0; i<stringArray.length; i++) {
      if(stringArray[i].indexOf(keyWords[j]) !== -1) {
        response.push(keyWords[j]);
      }
    }
  }

但它只返回确切的关键词，没有数字..

response = [data, data, action, action, type, type]

Answer 1

如果您想采用正则表达式方法，

这个例子可能就是你要找的：

var found = [],
    result;   

for(var i in stringArray){
   result = stringArray[i].match(/(data|action|value|type)(\d+)/);
   found.push(result);
}

在 "found" 数组中，您应该得到一个项目列表，每个项目都包含以下数据：

1. 原始关键字匹配（带数字的关键字字符串）
2. 关键字字符串部分（不含数字）
3. 仅数字（从关键字中提取）

示例输出：

[["data4", "data", "4"], ["data110", "data", "110"], ["action1023", "action", "1023"], ["type23", "type", "23"], ["action13", "action", "13"], ["type48", "type", "48"]]

希望对你有所帮助。

Answer 2

这段代码完成了这项工作

var keyWords = ["data","action","value","type"];

var stringArray = ["set data4 to custom value '1'",
               "set data110 to custom value '2'",
               "overwrite value of action1023 with new value",
               "set type23 to custom value '10'",
               "overwrite value of action13 with text",
               "set type48 to custom value '7'"]

var response = [];

for(var i = 0; i < stringArray.length; ++i){
    for(var j = 0; j < keyWords.length; ++j){
        if((index = stringArray[i].indexOf(keyWords[j])) !== -1){
            splittedStr = stringArray[i].substring(index,         stringArray[i].length).split(' ', 1);
            response.push(splittedStr[0]);
        }
    }
}
console.log(response);

Answer 3

非常直接的方法：

var keyWords = ["data","action","value","type"];

var stringArray = ["set data4 to custom value '1'",
                   "set data110 to custom value '2'",
                   "overwrite value of action1023 with new value",
                   "set type23 to custom value '10'",
                   "overwrite value of action13 with text",
                   "set type48 to custom value '7'"]

function f(keyWords, stringArray){
	let output = []
	
	stringArray.forEach((sentence) => {
		var words = sentence.split(' ')
	
		words.forEach((word) => {
			keyWords.forEach((keyword) => {			
				if(word.indexOf(keyword) > -1 ) {
					output.push(word)
				}				
			})
		})
	})
		
	return output
}

console.log(f(keyWords, stringArray))

Answer 4

...一种更通用和功能更强大的方法...

var
    keyList       = ["data", "action", "value", "type"],

    sentenceList  = [
        "set data4 to custom value '1'",
        "set data110 to custom value '2'",
        "overwrite value of action1023 with new value",
        "set type23 to custom value '10'",
        "overwrite value of action13 with text",
        "set type48 to custom value '7'"
    ],

    wordList = sentenceList.reduce(function collectSpecificWords (collector, sentence) {
        var
            matchList = sentence.split(/\s+/).filter(function (word) {

                return collector.regXWord.test(word);
            });

        collector.wordList = collector.wordList.concat(matchList);

        return collector;

    }, {

      //regXWord: RegExp("^("+ keyList.join("|") + ")[0-9]+$"),
        regXWord: RegExp("^("+ keyList.join("|") + ")[0-9]*$"),
        wordList: []

    }).wordList;


console.log("wordList : ", wordList);