根据 SQL Server 中的条件解析 JSON

Question

这是将要提供的 JSON 定义（只是一个简短的示例）以及我为获得预期结果而实现的代码：

declare @json nvarchar(max)

set @json = '{
   "testJson":{
      "testID":"Test1",
      "Value":[
         {
            "Value1":"",
            "Value2":"",
            "Value3":"",
            "Type": "1A"
         },
         {
            "Value1":"123",
            "Value2":"456",         
            "Value3":"Automatic",
            "Type": "2A"
         },
         {
            "Value1":"789",
            "Value2":"159",         
            "Value3":"Manual",
            "Value4":"Success"  ,
            "Type": "3A"
         }
      ]
   }
}'


select 
    'ValueFields' as groupDef,
    -- b.[key],
    -- c.[key],
    STRING_AGG( c.value , ' | ') as val
from 
    openjson(@json, '$.testJson.Value') as b
cross apply 
    openjson(b.value) as c
where 
    b.[key] not in (select b.[key]
                    from openjson(@json, '$.testJson.Value') as b
                    where b.value like ('%1A%'))

如您所见，数组中的每个元素都可以有不同数量的属性（value1,.., value4..），我只需要考虑那些 type 属性不等于“1A”的元素。该查询为我提供了请求的结果，但是，我想知道如何提高代码的性能，因为我在子选择中使用了 like 运算符，并且显然原始 JSON 文件可能在数组。

Answer 1

…

select b.Value --,c.value
from 
openjson(@json, '$.testJson.Value')
with
(
  Value nvarchar(max) '$' as json,
  Type varchar(100) '$.Type'
) as b
--cross apply  openjson(b.Value) as c
where b.Type <> '1A'

Answer 2

SELECT 
    'ValueFields' as groupDef,
    J.value as val
FROM
OPENJSON(@json,'$.testJson.Value') J
WHERE
    JSON_VALUE([value],'$.Type') <> '1A'