解析这个 JSONObject

Question

我对 android 开发真的很陌生......我有这个 JSONObject：

[
{
"IDalunno":"1",
"Username":"federicove",
"Password":"5ecb232b535685f95fa7bc19e436c79e",
"Nome":"Federico",
"Cognome":"Vergallo",
"Classe":"5",
"Sezione":"A",
"Indirizzo":"Informatica Abacus"
},
{
"0":{
"DataAssenza":"2013-09-26",
"TipoAssenza":"Ritardo"
},
"2":{
"DataAssenza":"2013-12-11",
"TipoAssenza":"Assenza"
},
"4":{
"DataAssenza":"2013-12-16",
"TipoAssenza":"Assenza"
}
},
[
{
"Materia":"Italiano",
"DataVoto":"2014-04-01",
"TipoVoto":"Scritto",
"Voto":"8"
},
{
"Materia":"Italiano",
"DataVoto":"2014-04-02",
"TipoVoto":"Orale",
"Voto":"7"
},
{
"Materia":"Storia",
"DataVoto":"2014-04-09",
"TipoVoto":"Orale",
"Voto":"7"
},
{
"Materia":"Inglese",
"DataVoto":"2014-03-04",
"TipoVoto":"Orale",
"Voto":"9"
},
{
"Materia":"Inglese",
"DataVoto":"2014-03-10",
"TipoVoto":"Orale",
"Voto":"8"
},
{
"Materia":"Matematica",
"DataVoto":"2014-02-03",
"TipoVoto":"Scritto",
"Voto":"8"
}
]
]

这是我的方法：

  protected String[] doInBackground(String...params) {
    String url = "http://federicovergallo.altervista.org/blog/prova.php";
    JSONParser sitoLogin = new JSONParser();
    try{
        JSONObject obj = sitoLogin.getJSONFromUrl(url, params);

        String[] risultatoLogin = new String [3];

        risultatoLogin[0] = obj.getString("IDalunno");
        risultatoLogin[1] = obj.getString("Nome");
        risultatoLogin[2] = obj.getString("Cognome");

        return risultatoLogin;
        //this doesn't work, it returns null everytime
    }
    catch (Exception e){

    }
    return null;
}

这是我的解析器：

// costruttore
public JSONParser() {

}

public JSONObject getJSONFromUrl(String url, String[] parametri) {

    // Preparo i dati da passare tramite POST
    ArrayList<NameValuePair> params = new ArrayList<NameValuePair>();
    params.add(new BasicNameValuePair("username", parametri[0]));
    params.add(new BasicNameValuePair("password", parametri[1]));
    // HTTP request
    Log.i("User", parametri[0]);
    Log.i("Password", parametri[1]);
    try {
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);
        httppost.setEntity(new UrlEncodedFormEntity(params));

        HttpResponse httpResponse = httpClient.execute(httppost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line);
        }
        is.close();
        json = sb.toString();
        Log.e("JSON", json);
    } catch (Exception e) {
        Log.e("Buffer Error", "Errore nella conversione " + e.toString());
    }

    //trasformo la stringa in un oggetto JSON
    //se abbiamo fatto errori lato server, qui vengono fuori ;)
    try {
        jObj = new JSONObject(json);            
    } catch (JSONException e) {
        Log.e("JSON Parser", "Errore nel parse " + e.toString());
    }

    // return l'oggetto JSONObject
    return jObj;

}

}

我必须将所有信息（从“IDalunno”和“用户名”到“TipoVoto”和“Voto”）保存在一个字符串数组中，但我真的不知道如何......每个提示都可能很珍贵。

编辑：我发现，我必须在我的方法 getJSONFromUrl 中返回一个 JSONArray，然后使用 obj.getJSONObject(0).getString("IDalunno") 访问该数组

Answer 1

查看文档，首先，尝试任何方法:)

http://developer.android.com/reference/org/json/package-summary.html

Answer 2

例如，您将 json 对象存储在变量 data

var data = {
"number": "001",
"name": "Jill",
"date": "2014. January 01."
}

{
"number": "002",
"name": "John",
"date": "2014. March 03."
}

您可以像这样检索每个元素：

data[0].number // is 001
data[1].number // is 002

data[0].name  // is Jill
data[1].name  // is John

data[0].date // is 2014. January 01.
data[1].date // is 2014. March 03.

一旦您知道如何检索每个元素，您就可以按照自己喜欢的方式保存它（使用循环或其他方式）

Answer 3

var data = [{
"number": "001",
"name": "Jill",
"date": "2014. January 01."
},
{
"number": "002",
"name": "John",
"date": "2014. March 03."
}];

var ArrayName = new Array(); 
var ArrayNumber = new Array();
var ArrayDate = new Array();  

int i=0;

data.forEach(function(v){

   ArrayName[i]=v.name;
   ArrayNumber[i]=v.number;
   ArrayDate[i]=v.date
   i=i+1;

});