当我在结构中包含多个数组时，我的程序跳过了一堆代码

Question

我正在尝试学习 C++ 中的结构。当我像这样运行我的代码时：

#include<iostream>
using namespace std;

struct person{
    char firstName[50];
    int age;
    float gradYear;
};
int main(){
    person p1;

    cout << "Whats your FIRST name?";
    cin.get(p1.firstName, 50);
    cout << "Whats your AGE?";
    cin >> p1.age;
    cout << "Whats your GRADUATION YEAR?";
    cin >> p1.gradYear;

    cout << "Displaying Your Information . . . " << endl;
    cout << "First Name: " << p1.firstName << endl;
    cout << "Age: " << p1.age << endl;
    cout << "Graduation Year: " << p1.age << endl;

    return 0;
}

代码按我的意愿工作，但是当我像这样运行代码时：

#include<iostream>
using namespace std;

struct person{
    char firstName[50];
    char lastName[50];
    int age;
    char branch[50];
    float gradYear;
};
int main(){
    person p1;

    cout << "Whats your FIRST name?";
    cin.get(p1.firstName, 50);
    cout << "Whats your LAST name?";
    cin.get(p1.lastName, 50);
    cout << "Whats your AGE?";
    cin >> p1.age;
    cout << "Are you Corps or Civilian?";
    cin >> p1.branch;
    cout << "Whats your GRADUATION YEAR?";
    cin >> p1.gradYear;

    cout << "Displaying Your Information . . . " << endl;
    cout << "First Name: " << p1.firstName << endl;
    cout << "Last Name: " << p1.lastName << endl;
    cout << "Age: " << p1.age << endl;
    cout << "Branch: " << p1.branch << endl;
    cout << "Graduation Year: " << p1.age << endl;

    return 0;
}

在我输入名字后，代码会输出信息。为什么会这样做，我怎样才能让它以第二种方式工作？

Answer 1

发生这种情况是因为cin.get() 方法输入了名字，当您按下回车键时，回车键被输入到所有其他输入中。这是一个意外的行为......

您可以通过在输入之间写入getch() 来克服这个问题。

我的意思是..

    cout << "Whats your FIRST name?"; 
cin.get(p1.firstName, 50); 
    getch();
    cout << "Whats your LAST name?"; 
cin.get(p1.lastName, 50);
    getch();
    cout << "Whats your AGE?"; 
    cin >> p1.age; 
    getch();
    cout << "Are you Corps or Civilian?";
    cin >> p1.branch;
    getch();
    cout << "Whats your GRADUATION YEAR?";
    cin >> p1.gradYear;
    getch();