【发布时间】:2018-12-20 08:22:28
【问题描述】:
我编写了一个公式来读取 txt 文件,将其存储在数组(1D)中,然后读取数组以计算移动平均值(2D)。程序要求用户输入两个值(k1 & k2)并计算从k1 到k2 的每个值的移动平均值(基本上是找出最佳值)
以下是代码
#include<stdlib.h>
#define MAX_FILE_NAME 100
#define MAXCHAR 1000
int main()
{
FILE *fp;
int count = 0,k1=0,k2=0,k=0; // Line counter (result)
int buy[k2][count],sell[k2][count];
char filename[MAX_FILE_NAME];
char c; // To store a character read from file
// Get file name from user. The file should be
// either in current folder or complete path should be provided
printf("Enter file name or full path: ");
scanf("%s", filename);
printf("Enter the minimum rolling period for calculation : \n");
scanf("%d", &k1);
printf("Enter the maximum rolling period for calculation : \n");
scanf("%d", &k2);
// Open the file
fp = fopen(filename, "r");
// Check if file exists
if (fp == NULL)
{
printf("Could not open file %s", filename);
return 0;
}
// Extract characters from file and store in character c
for (c = getc(fp); c != EOF; c = getc(fp))
if (c == '\n') // Increment count if this character is newline
count = count + 1;
// Close the file
fclose(fp);
//printf("The file %s has %d lines\n", filename, count);
FILE *myFile;
myFile = fopen(filename, "r");
//read file into array
float numberArray[count];
int i;
if (myFile == NULL){
printf("Error Reading File\n");
exit (0);
}
for (i = 0; i < count; i++){
fscanf(myFile, "%f,", &numberArray[i]);
}
fclose(myFile);
for (k=k1;k<=k2;k++)
{
float n;
float data[count],mag[k2][count];
double avg,sum;
for (i=0;i<k-1;i++)
{
mag[k][i-1]=0;
sum=sum+numberArray[i];
}
for(i=k-1;i<=count;i++)
{
mag[k][i-1]=avg;
sum=sum+numberArray[i]-numberArray[i-k];
avg = sum/k;
}
// for(i=0;i<=count;i++)
// {
// printf("MA[%d][%d] = %0.2lf ",k,i,mag[k][i]);
// if (i%3==0)
// printf("\n");
// }
}
for(k=k1;k<=k2;k++)
{
for(i=0;i<=count;i++)
printf("MA[%d][%d] = %0.2lf ",k,i,mag[k][i]);
}
}
}
现在,当我尝试在 for 循环之外打印 mag[k][i] 值时,它显示错误“mag”未声明。但是当我将打印命令放入循环中时(代码中的注释部分),它工作正常。
以下评论后更新的代码(仍然无法正常工作)
#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<stdlib.h>
#define MAX_FILE_NAME 100
#define MAXCHAR 1000
int main()
{
FILE *fp;
int count,k1,k2,k; // Line counter (result)
char filename[MAX_FILE_NAME];
char c; // To store a character read from file
// Get file name from user. The file should be
// either in current folder or complete path should be provided
printf("Enter file name or full path: ");
scanf("%s", filename);
printf("Enter the minimum rolling period for calculation : \n");
scanf("%d", &k1);
printf("Enter the maximum rolling period for calculation : \n");
scanf("%d", &k2);
// Open the file
fp = fopen(filename, "r");
// Check if file exists
if (fp == NULL)
{
printf("Could not open file %s", filename);
return 0;
}
// Extract characters from file and store in character c
for (c = getc(fp); c != EOF; c = getc(fp))
if (c == '\n') // Increment count if this character is newline
count = count + 1;
// Close the file
fclose(fp);
//printf("The file %s has %d lines\n", filename, count);
/****************
File opening and reading section
*****************************************************/
FILE *myFile;
myFile = fopen(filename, "r");
//read file into array
float numberArray[count];
int i;
if (myFile == NULL){
printf("Error Reading File\n");
exit (0);
}
for (i = 0; i < count; i++){
fscanf(myFile, "%f,", &numberArray[i] );
}
fclose(myFile);
/***********************************************
Calculation of Moving Average and storing it in array
******************************************/
int buy[k2][count],sell[k2][count];
float mag[k2][count];
for (k=k1;k<=k2;k++)
{
float data[count];
double avg,sum;
for (i=1;i<k;i++)
{
mag[k][i-1]=0;
sum=sum+numberArray[i];
}
for (i=k-1;i<=count;i++)
{
mag[k][i-1]=avg;
sum=sum+numberArray[i]-numberArray[i-k];
avg = sum/k;
}
// for(i=0;i<=count;i++)
// {
// printf("MA[%d][%d] = %0.2lf ",k,i,mag[k][i]);
// if (i%3==0)
// printf("\n");
// }
}
for (k=k1;k<=k2;k++)
{
for (i=0;i<=count;i++)
{
printf("MA[%d][%d] = %0.2lf ",k,i,mag[k][i]);
}
}
}
【问题讨论】:
-
欢迎来到 SO。您可以通过正确缩进来大大提高代码的可读性。这将吸引更多读者。
-
int buy[k2][count],sell[k2][count];在这一行count包含 0。这可能不是你想要的。 -
您可能会更新您的问题以显示新代码。使用“编辑”按钮并将修改后的代码添加到旧代码下方。不鼓励删除旧代码,因为它会使所有 cmets 和答案无用。
-
mag[k][i-1]=0;在那个循环中,k运行到<=k2太多了,i从 0 开始,使得i-1有点太低了。 -
char c必须是int c否则您可能无法正确检测到 EOF。
标签: c arrays multidimensional-array