【发布时间】:2016-04-20 03:07:37
【问题描述】:
我需要为这段代码使用指针。没有数组,没有结构。例如,如果我需要一个浮点数组来保存分数,请不要使用浮点分数 [15]。而是使用 float *score,然后使用动态内存分配来保存所需的内存。我必须以最佳方式使用内存,也就是说,如果您只有 6 个分数,我需要使用它来指向 sizeof(float)*6 字节的内存块。同样,要保存名称,而不是使用 2D char 数组,使用 2D 指针 (char firstName[15][20] → char **firstName)。
我有下面的 C 代码,我需要使用 2d 指针的帮助。代码编译并运行,但是在我输入名称后,如果崩溃并且在处理它这么长时间后我被卡住了。
提前谢谢你
#include <stdio.h>
#include<string.h>
#include<stdlib.h>
#include<time.h>
void Option_Scren();
void print_records(int size, char **firstname, char **lastname, float *score);
void search_by_firstname(int size, char **firstname, char **lastname, float *score);
void search_by_lastname(int size, char **firstname, char **lastname, float *score);
void sort_by_score(int size, char **firstname, char **lastname, float *score);
void sort_by_lastname(int size, char **firstname, char **lastname, float *score);
int main(void)
{
char **First_Name;
char **Last_Name;
float *Score_;
int n = 0;
int i = 0;
int x = -1;
First_Name = (char **)malloc(sizeof(char *));
Last_Name = (char **)malloc(sizeof(char *));
Score_ = (float *)malloc(sizeof(int)*15);
for(i=0; i<15; i++)
{
First_Name[i] = (char *)malloc(20*sizeof(char));
Last_Name[i] = (char *)malloc(20*sizeof(char));
}
//char *nametofind = (char *)malloc(20*sizeof(char));
printf("Please indicate the number of records you want to enter (min 5, max 15):\n");
scanf("%d", &n);
printf("Please input records of students (enter a new line after each record), with the following format \nFirstname Lastname Score\n");
for (i = 0; i<n; i++)
{
scanf("%s %s %f", &First_Name[i][0], &Last_Name[i][0], &Score_[i]);
}
do
{
printf("\n---you may access the records by---\n");
printf("Print records (press 1)\n");
printf("Search by first name (press 2)\n");
printf("Search by last name (press 3)\n");
printf("Sort by score (press 4)\n");
printf("Sort by last name (press 5)\n");
printf("Exit program (press 0)\n");
printf("--------------------------\n\n");
printf("Please a function by entering a value from 0 to 5.\n");
scanf("%d", &x);
printf("You have selected option: %d\n", x);
switch (x)
{
case 1:
print_records(n, First_Name, Last_Name, Score_);
break;
case 2:
search_by_firstname(n, First_Name, Last_Name, Score_);
break;
case 3:
search_by_lastname(n, First_Name, Last_Name, Score_);
break;
case 4:
sort_by_score(n, First_Name, Last_Name, Score_);
break;
case 5:
sort_by_lastname(n, First_Name, Last_Name, Score_);
break;
default: printf("Please only enter a number from 0 to 5\n");
}
}
while (x != 0);
printf("Thank You \nGood Bye\n");
return 0;
}
void print_records(int size, char **firstname, char **lastname, float *score)
{
int i = 0;
for (i = 0; i < size; i++)
{
printf("First Name: %s, Last Name: %s, Score: %.2f\n", firstname[i], lastname[i], score[i]);
}
}
void search_by_firstname(int size, char **firstname, char **lastname, float *score)
{
int i = 0;
char *Name_Search = (char *)malloc(20*sizeof(char));
printf("Please enter the first name of student record you wish to print: ");
fgets(Name_Search, 20, stdin);
for (i = 0; i<size; i++)
{
if (strcmp(Name_Search, firstname[i]) == 0)
{
printf("First Name: %s, Last Name: %s, Score: %.2f\n", firstname[i], lastname[i], score[i]);
}
}
}
void search_by_lastname(int size, char **firstname, char **lastname, float *score)
{
int i = 0;
char *Name_Search = (char *)malloc(20*sizeof(char));
printf("Please enter last name of student record you wish to print: ");
fgets(Name_Search, 20, stdin);
for (i = 0; i<size; i++)
{
if (strcmp(Name_Search, lastname[i]) == 0)
{
printf("First Name: %s, Last Name: %s, Score: %.2f\n", firstname[i], lastname[i], score[i]);
}
}
}
void sort_by_score(int size, char **firstname, char **lastname, float *score)
{
int i = 0;
int j = 0;
float tempscore;
char tempfirstname[20];
char templastname[20];
// bubble sort
for (i = 0; i<size - 1; i++)
{
for (j = 0; j<size - i - 1; j++)
{
if (score[j]>score[j + 1])
{
tempscore = score[j];
score[j] = score[j + 1];
score[j + 1] = tempscore;
strcpy(tempfirstname, firstname[j]);
strcpy(firstname[j], firstname[j + 1]);
strcpy(firstname[j + 1], tempfirstname);
strcpy(templastname, lastname[j]);
strcpy(lastname[j], lastname[j + 1]);
strcpy(lastname[j + 1], templastname);
}
}
}
print_records(size, firstname, lastname, score);
}
void sort_by_lastname(int size, char **firstname, char **lastname, float *score)
{
int i = 0;
int j = 0;
float tempscore;
char tempfirstname[20];
char templastname[20];
// bubble sort
for (i = 0; i<size - 1; i++)
{
for (j = 0; j<size - i - 1; j++)
{
if (strcmp(lastname[j], lastname[j + 1])>0)
{
strcpy(tempfirstname, firstname[j]);
strcpy(firstname[j], firstname[j + 1]);
strcpy(firstname[j + 1], tempfirstname);
strcpy(templastname, lastname[j]);
strcpy(lastname[j], lastname[j + 1]);
strcpy(lastname[j + 1], templastname);
tempscore = score[j];
score[j] = score[j + 1];
score[j + 1] = tempscore;
}
}
}
print_records(size, firstname, lastname, score);
}
【问题讨论】:
-
你试过自己调试吗?你能给出一个错误的输出吗?
-
在分配内存之前,需要询问用户他们想要多少条记录。
-
我尝试在调用记录之前移动它,但它仍然崩溃。
-
一些小问题 - 你应该添加一个
case 0: break;。否则你会下拉到default:并错误地打印错误信息 -
这些限制是针对真实代码的还是仅仅是一个分配?如果是后者,你的导师真的很糟糕。我不明白为什么还要在课堂上教授伪数组。
标签: c arrays string pointers 2d