【发布时间】:2014-08-02 08:35:23
【问题描述】:
这是我的任务:
创建一个程序,允许用户输入最多 10 个朋友的地址。使用二维数组存储朋友的地址。输入每个地址后,用户应该可以选择输入另一个地址或打印一份报告,显示迄今为止输入的每个地址。
我得到了大部分,但我的主要问题是 fgets。我不断收到此错误:
warning: passing arg 1 of `fgets' makes pointer from integer without a cast
代码:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main ()
{
char name[20]= {0};
char address[40]= {100};
int choice;
int i;
printf("Welcome to the Address Book!\n\n");
for (i=0;i<10;i++) //start of the array loop. should give an exit after each entry
{
printf("Would you like to (1)Enter an address, or (2)Print the address book?\n");
scanf("%i",&choice);
switch (choice)
{
case 1:
{
printf("Please enter a name...\n");
fgets(name[i],20,stdin);
printf("You entered %s .", name);
printf("Please enter an address...\n");
fgets(address[i],40,stdin);
printf("You enteres %s .", address);
}
break;
case 2:
for (i = 0; i<10; i ++)
{
printf("%s\n", name[i]);
printf("%s\n", address[i]);
}
break;
}
}
return (0);
}
【问题讨论】:
-
fgets(name[i],20,stdin);-->fgets(name,20,stdin);或fgets(name,sizeof name,stdin);和scanf("%i",&choice);的换行符 -
你的二维数组在哪里?
-
char name[20]= {0};-->char name[10][20]= {0};