将多维数组上嵌套数组的数组键从整数更改为字母

Question

array (
  'A' => 
  array (
    'topic' => 'My topic name',
    'starttime' => '12/11/2018 16:30:00',
    'endtime' => '12/11/2018 18:00:00',
    'webinarid' => '1235',
    'webinarkey' => '123518238123',
    'orgkey' => '',
    'regurl' => 'https://attendee.gotowebinar.com/register/xxx',
    'description' => 'Long desc',
    'newsletteremailid' => '321',
    'ogimage' => 'https://xxx',
    'presenterurl' => 'https://xxx',
    'elite' => '1',
    'postid' => '699599',
  ),
  'B' => 
  array (
    'topic' => 'Topic title',
    'starttime' => '12/4/2018 16:30:00',
    'endtime' => '12/4/2018 18:00:00',
    'webinarid' => '123512',
    'webinarkey' => '8127317327132',
    'orgkey' => '',
    'regurl' => 'https://attendee.gotowebinar.com/register/xxx',
    'description' => 'Topic description',
    'newsletteremailid' => '316',
    'ogimage' => 'https://xxx',
    'presenterurl' => '',
    'elite' => '1',
    'postid' => '8235123'
    )
)

我试图将每个嵌套数组从 0..x 转换为字母表。所以例如'topic'是'A'，'orgkey'是'F'。

然后返回一个新的多维数组（'A' => array('A' => 'My topic name', 'B' => '12/11/2018 16:30:00')）等等.

Answer 1

创建一个字母数组并循环遍历该数组，用相同索引处的字母替换键。

https://paiza.io/projects/_ICIlEET4tieXtsN4MF4rw

$alph = array('A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z');

$arr=array('A'=>array('topic'=>'My topic name','starttime'=>'12/11/2018 16:30:00','endtime'=>'12/11/2018 18:00:00','webinarid'=>'1235','webinarkey'=>'123518238123','orgkey'=>'','regurl'=>'https://attendee.gotowebinar.com/register/xxx','description'=>'Long desc','newsletteremailid'=>'321','ogimage'=>'https://xxx','presenterurl'=>'https://xxx','elite'=>'1','postid'=>'699599'),'B'=>array('topic'=>'Topic title','starttime'=>'12/4/2018 16:30:00','endtime'=>'12/4/2018 18:00:00','webinarid'=>'123512','webinarkey'=>'8127317327132','orgkey'=>'','regurl'=>'https://attendee.gotowebinar.com/register/xxx','description'=>'Topic description','newsletteremailid'=>'316','ogimage'=>'https://xxx','presenterurl'=>'','elite'=>'1','postid'=>'8235123'));

$newArr = array();
foreach($arr as $key1 => $val1){
    $i=0;
    foreach($val1 as $key2 => $val2){
        $newKey = "";
        //this if/else statement sets the key from A-Z, then AA, AB, etc.
        if($i > count($alph) - 1){
            $newKey = $alph[floor($i / count($alph)-1)].$alph[$i % count($alph)];
        }else{
            $newKey = $alph[$i];
        }
        $newArr[$key1][$newKey] = $val2;
        $i++;
    }
}

print_r($newArr);

Answer 2

您没有任何整数/数字键；但假设它们已经按正确的顺序排列，只需创建一系列字母并将这些键与现有值组合。这只适用于Z。然后转至AA 等。会涉及更多，可能需要问另一个问题：

foreach($array as &$values) {
    $values = array_combine(range(chr(65), chr(64+count($array))), $values);
}

如果它们不按顺序排列，那么您必须分配每个：

foreach($array as $key => $values) {
    $result[$key] = ['A' => $values['topic'], 'B' => $values['starttime']]; // etc...
}

我真的想不出任何理由这样做，因此您可能需要重新考虑您的方法。

Answer 3

array_walk($data, function(&$value){
    $keys = array_splice(range('A', 'Z', 1), 0, count($value));
    $value = array_combine($keys, $value);
});

这适用于任何长度的数据数组......最多 26 个项目