【发布时间】:2016-06-08 16:40:08
【问题描述】:
我的问题太扭曲了,我什至不知道如何开始解释它。
假设我有几个关联数组(并不总是相同的数组:有时我有产品数组,有时我有市场数组,有时我有段数组,等等......)。 $values 是我总是得到的唯一数组!
$values = array ("0" => "1", "4" => "2", "5" => "3");
$products = array ("0" => "1", "1" => "1", "2" => "2", "3" => "1", "4" => "2", "5" => "3");
$markets = array ("0" => "1", "3" => "1", "4" => "2", "5" => "3");
...
我想用我得到的每个数组的值构建一个数组,其中的值与键匹配。 类似的东西
$myArray = array ("0" => array ( "values" => "1", "products" => "1", "markets" => "1"),
"1" => array ( "products" => "1"),
"2" => array ( "products" => "2"),
"3" => array ( "products" => "1", "markets" => "1"),
"4" => array ( "values" => "2", "products" => "2", "markets" => 2),
...);
我尝试过这样的事情:
switch ($_POST["cpv_type"]) {
case "pClass":
$keyValue = $_POST["cpv_type"];
$objKey = "this->productClasses";
break;
case "pMarket":
$keyValue = $_POST["cpv_type"];
$objKey = "this->markets";
break;
case "pSegment":
$keyValue = $_POST["cpv_type"];
$objKey = "this->productSegments";
break;
case "pType":
$keyValue = $_POST["cpv_type"];
$objKey = "this->productTypes";
break;
default:
$keyValue = "products";
$objKey = "this->products";
break;
}
然后我做一个foreach cicle:
// all values must be floats
if(!empty($this->value)){
foreach ($this->value as $key => &$curVal){
// if no value has been entered, exclude it and also associated product from validation
if (strlen(trim($curVal)) == 0) {
unset($this->value[$key]);
unset($this->products[$key]);
} else {
// This validates my variable
$curVal = TMS::checkVar($curVal, "dec", $_SESSION["dico"]->_VALUE_, 100, false);
// Store the value on existing array, associating "hoppValue" to the right key entry!
$logDetail[$keyValue][${$objKey}[$key]]["hoppValue"] = $curVal;
}
}
}
我的问题出在变量变量中:
如何使用可变变量语法访问,例如$this->productTypes[5]?
对于$$objKey、${$objKey}、${$objKey}[$key]、${$objKey[$key]}、$$objKey[$key] 的所有 var_dump,我得到“null”
感谢您的帮助!
【问题讨论】:
-
如果`$objKey = $this->productClasses`可以简单的获取数组并用作
$objKey[$key] -
你完全正确!答案如此简单,就在我眼前。工作日不应该这么长! (请将您的评论放入答案中,以便我将其标记为正确!)
标签: php arrays variables dynamic-variables