如何从 2 个带有 ES6 Javascript 对象的数组中获取相同的值？答案

【问题标题】：How to get same values from 2 arrays with objects in ES6 Javascript?如何从 2 个带有 ES6 Javascript 对象的数组中获取相同的值？
【发布时间】：2021-09-12 07:37:26
【问题描述】：

所以我这里有两个不同的数组。

const test = [
    { firstName: "John", lastName: "Doe" },
    { firstName: "Michael", lastName: "Sins" },
    { firstName: "Alex", lastName: "Brown" }
  ];

const test2 = [
    { firstName: "Lisa", lastName: "Shore" },
    { firstName: "John", lastName: "Doe" },
    { firstName: "Justin", lastName: "Park" },
  ];

我想要的是使用 ES6（如果可能，进行过滤）或以任何适合实现输出的方式从两个数组中获取相同的值。我想要得到的结果是：

[{ firstName: "John", lastName: "Doe" }]

【问题讨论】：

你尝试过什么代码来解决这个问题？您应该将其作为minimal reproducible example 添加到问题中。
这能回答你的问题吗？ Simplest code for array intersection in javascript

标签： javascript arrays object ecmascript-6

【解决方案1】：

您可以尝试使用Array.prototype.filter() 和Array.prototype.some()

const test = [
    { firstName: "John", lastName: "Doe" },
    { firstName: "Michael", lastName: "Sins" },
    { firstName: "Alex", lastName: "Brown" }
  ];

const test2 = [
    { firstName: "Lisa", lastName: "Shore" },
    { firstName: "John", lastName: "Doe" },
    { firstName: "Justin", lastName: "Park" },
  ];

const res = test.filter(t1 => test2.some(t2 => 
                    t1.firstName == t2.firstName 
                    && t1.lastName == t2.lastName
                  ));
console.log(res);

【讨论】：

【解决方案2】：

如果您的对象具有除firstName 和lastName 以外的属性，则此泔水仍然有效

const test = [
    { firstName: "John", lastName: "Doe" },
    { firstName: "Michael", lastName: "Sins" },
    { firstName: "Alex", lastName: "Brown" }
  ];
  
  const test2 = [
    { firstName: "Lisa", lastName: "Shore" },
    { firstName: "John", lastName: "Doe" },
    { firstName: "Justin", lastName: "Park" },
  ];
  
  const tempTest2 = test2.map(item => JSON.stringify(item));
  
  const result = test.filter(item => tempTest2.includes(JSON.stringify(item)));
  
  console.log(result);

【讨论】：

【解决方案3】：

你可以这样做：

const test = [{ firstName: 'John', lastName: 'Doe' },{ firstName: 'Michael', lastName: 'Sins' },{ firstName: 'Alex',lastName: 'Brown' }]
const test2 = [{ firstName: 'Lisa', lastName: 'Shore' },{ firstName: 'John', lastName: 'Doe' },{ firstName: 'Justin',lastName: 'Park' }]


const getFullName = ({ firstName, lastName }) => firstName + lastName
const test2Names = test2.map(getFullName)
const result = test.filter((o) => test2Names.includes(getFullName(o)))

console.log(result)

【讨论】：