从数组对象中删除键只显示值

Question

---

我有一个这样的数据

[
  {
    "3": "Foundation in Business",
    "4": "0",
    "5": "1103267.5",
    "6": "4277417.5",
    "7": "5168625",
    "8": "6241805",
    "9": "7383665",
    "10": "8236385",
    "11": "8645050",
    "12": "2494100",
    "13": "155555"
  }
  ]

我想要这样

数据：[ “商业基础”， "0", "1103267.5", "4277417.5", "5168625", "6241805", "7383665", "8236385", "8645050", "2494100", “155555” ]

请帮帮我...

Answer 1

在 ES6 中，映射值并获取 Object 值。因为结果是另一个数组得到第一个元素。如果你有一个对象数组，你可以通过删除脚本末尾的 [0] 来获得一个数组数组。

const jsonObject = [{
    "3": "Foundation in Business",
    "4": "0",
    "5": "1103267.5",
    "6": "4277417.5",
    "7": "5168625",
    "8": "6241805",
    "9": "7383665",
    "10": "8236385",
    "11": "8645050",
    "12": "2494100",
    "13": "155555"
}];
const data = jsonObject.map(v => Object.values(v))[0];
console.log(data);

在跨浏览器支持的标准中，您可以这样做：

   const jsonObject = [{
    "3": "Foundation in Business",
    "4": "0",
    "5": "1103267.5",
    "6": "4277417.5",
    "7": "5168625",
    "8": "6241805",
    "9": "7383665",
    "10": "8236385",
    "11": "8645050",
    "12": "2494100",
    "13": "155555"
}];
var array = [];
for (var name in jsonObject[0]) {
  console.log(name);
  array.push(jsonObject[0][name]);
}
console.log(array);