如何从 Python turtle 的特定位置开始绘图？答案

【问题标题】：How can I start drawing from a specific place in Python turtle?如何从 Python turtle 的特定位置开始绘图？
【发布时间】：2021-11-18 06:12:31
【问题描述】：

我正在尝试画草，我正在努力让我的画从左下角开始，然后一直到右下角。我知道我的代码有问题，但无法弄清楚。

我的代码是从中间开始的，这不是我想要的。

import turtle
import random

window = turtle.Screen()
bob = turtle.Turtle()
window.bgcolor("white")
window.title("TURTLE")
bob.pencolor("green")

window.colormode(255)


position = 0
height = 0
height11 = 0
height12 = 0
height13 = 0
height14 = 0
def draw_grass(bob):
    green = random.randint (100, 200)
    length = random.randint(10,20)
    bob.fillcolor(0,green,0)
    bob.begin_fill()
    bob.setheading(90)
    for i in range (2):
        
        bob.forward(length)
        bob.right(90) 
        bob.forward(3)
        bob.right(90)
    bob.end_fill()
    bob.penup()
    bob.pendown()
    return length
for i in range (10):
    height = draw_grass(bob)
    position = position + 3
    bob.goto(position, 0)
    if height == 11 :
        height11 = height11 + 1
    elif height == 12:
        height12 = height12 + 1
    elif height == 13:
        height13 = height13 + 1

【问题讨论】：

标签： python turtle-graphics python-turtle

【解决方案1】：

您需要了解原点(0, 0) 位于窗口的中心，并且您必须使用正数和负数。 screen 方法window_width() 和window_height() 对于确定您没有自己配置的窗口的大小很有用。以下是包含这些想法的代码修改：

from turtle import Screen, Turtle
from random import randint

def draw_grass(turtle):
    green = randint(100, 200)
    length = randint(10, 20)
    turtle.fillcolor(0, green, 0)

    turtle.begin_fill()

    for _ in range(2):
        turtle.forward(3)
        turtle.left(90)
        turtle.forward(length)
        turtle.left(90)

    turtle.end_fill()

    turtle.penup()
    turtle.pendown()

    return length

screen = Screen()
screen.bgcolor('white')
screen.title("TURTLE")
screen.colormode(255)

turtle = Turtle()
turtle.pencolor('green')
turtle.speed('fastest')  # because I have no patience

turtle.penup()
turtle.setposition(6 - screen.window_width()//2, 12 - screen.window_height()//2)
turtle.pendown()

height11 = 0
height12 = 0
height13 = 0
height14 = 0

while turtle.xcor() < screen.window_width()//2 - 6:
    height = draw_grass(turtle)

    if height == 11:
        height11 += 1
    elif height == 12:
        height12 += 1
    elif height == 13:
        height13 += 1
    elif height == 14:
        height14 += 1

    turtle.forward(3)

screen.exitonclick()

【讨论】：