PHP合并和重新排列2个或更多数组答案

【问题标题】：PHP merge and rearrange 2 or more arraysPHP合并和重新排列2个或更多数组
【发布时间】：2017-03-29 06:59:31
【问题描述】：

它将有 2 个或更多的数组从 foreach 循环中出来。喜欢关注

array1 
    [0] => Array
        (
            [0] => 1207
            [1] => 4
            [2] => haha.mp4
        )

    [1] => Array
        (
            [0] => 1208
            [1] => 4
            [2] => hehe.mp4
        )

array2
   [0] => Array
        (
            [0] => 1209
            [1] => 16
            [2] => SampleVideo.mp4
        )

    [1] => Array
        (
            [0] => 1210
            [1] => 16
            [2] => 295.mp4
        )

我想从这两个数组中获取相同的索引值，然后像这样合并这些数组。

**FinalArray = array1[0],array2[0],array1[1],array2[1]**

例如

FinalArray

    [0] => Array
        (
            [0] => 1207
            [1] => 4
            [2] => haha.mp4
        )
    [1] => Array
        (
            [0] => 1209
            [1] => 16
            [2] => SampleVideo.mp4
        )

    [2] => Array
        (
            [0] => 1208
            [1] => 4
            [2] => hehe.mp4
        )


    [3] => Array
        (
            [0] => 1210
            [1] => 16
            [2] => 295.mp4
        )

请帮助如何获取相同的索引值并合并这 2 个数组。谢谢

【问题讨论】：

放你的foreach循环？

标签： php arrays multidimensional-array array-merge

【解决方案1】：

您可以通过使用array_column 和array_merge 的一个循环来实现这一点，如下所示，

$array1 = array(
    0 => [0 => 1207, 1 => 4, 2 => "haha.mp4"],
    1 => [0 => 1208, 1 => 4, 2 => "hehe.mp4"],
);

$array2 = array(
    0 => [0 => 1209, 1 => 16, 2 => "SampleVideo.mp4"],
    1 => [0 => 1210, 1 => 16, 2 => "295.mp4"],
);

// here I assume that the following array is the output of your foreach loop
$array = [$array1, $array2];
$list = [];
foreach ($array as $key => $value) {
    $list = array_merge($list, array_column($array, $key));
}

print_r($list);

现场演示：https://3v4l.org/2chf5

【讨论】：

【解决方案2】：

桑迪，我是来把你从废话中解救出来的。此页面上的所有方法都使用了太多的循环或太多的函数。最佳做法如下所示：

代码：(Demo)

$array1 = array(
    0 => [0 => 1207, 1 => 4, 2 => "haha.mp4"],
    1 => [0 => 1208, 1 => 4, 2 => "hehe.mp4"],
);

$array2 = array(
    0 => [0 => 1209, 1 => 16, 2 => "SampleVideo.mp4"],
    1 => [0 => 1210, 1 => 16, 2 => "295.mp4"],
);

foreach($array1 as $k=>$v){
    $result[]=$v;
    // if $array2 always has a matching key:
    $result[]=$array2[$k];
    // if it is possible that $array2 doesn't have a matching key:
    // if(isset($array2[$k]){$result[]=$array2[$k];}
    //... if you have more arrays to include, just repeat like: $result[]=$array3[$k];
}
var_export($result);

输出：

array (
  0 => 
  array (
    0 => 1207,
    1 => 4,
    2 => 'haha.mp4',
  ),
  1 => 
  array (
    0 => 1209,
    1 => 16,
    2 => 'SampleVideo.mp4',
  ),
  2 => 
  array (
    0 => 1208,
    1 => 4,
    2 => 'hehe.mp4',
  ),
  3 => 
  array (
    0 => 1210,
    1 => 16,
    2 => '295.mp4',
  ),
)

【讨论】：

【解决方案3】：

$result = array_merge($array1, $array2);
print_r($result);

来自： http://php.net/manual/en/function.array-merge.php

【讨论】：

感谢您的回答。我不想简单地合并这些数组。我想合并相同的索引值，如下所示。 FinalArray = array1[0],array2[0],array1[1],array2[1]
那么我猜你将不得不使用 foreach($key => $value) 遍历它们并手动排列它们
是的，我知道我的循环。但需要动态 foreach ($out as $key => $value) { if($key == 0) { $room0 = array_merge($room0,$value); } if($key == 1) { $room1 = array_merge($room1,$value); } }

【解决方案4】：

要获得元素顺序为array0[0],array1[0],array0[1],array1[1] 的finalArray，首先计算$max_elements，然后执行嵌套循环，检查该数组中是否存在$i 的元素：

$arrays = [$array0, $array1];
$max_elements = 0;
foreach($arrays as $array){
    $max_elements = max($max_elements, count($array));
}
$merged = []
for($i = 0; $i < $max_elements; $i++){
    foreach($arrays as $array){
        if($array[$i]){
            $merged[] = $array[$i];
        }
    }
}

【讨论】：