Perl 语法错误：Bareword found where operator expected

Question

正如标题所示，我该如何做到这一点？

我一直在学习一个教程，但是我收到了一个语法错误：

Bareword found where operator expected at arrays_and_variables.pl line
26, near "$2names"
        (Missing operator before names?) syntax error at
arrays_and_variables.pl line 26, near "$2names " Execution of
arrays_and_variables.pl aborted due to compilation errors.

我目前的代码是：

@names = ('james','dylan','max');

# join elements of array into a schalar variable.
$2names = join ('', @names);
print $s2names;

Answer 1

2names 是无效的变量名。名称不能以数字开头——它们必须以字母或下划线开头。