从一个包含所有意大利语单词的txt文件创建一个列表，python

Question

我从这里 (https://sourceforge.net/project/showfiles.php?group_id=128318&package_id=141110) 下载了一本包含所有意大利语单词的字典。我想将它们添加到列表中，以便可以使用 randint(0, list.count()) 将随机意大利语单词用作字符串。 小程序基本上就是“猜字”。 我使用了本指南：Creating a list of every word from a text file without spaces, punctuation 来查看我可以做些什么来实现这一点，但我收到了 ascii 代码错误。然后我尝试用有效字符 (àèèìù) 替换奇数字符 (‡ËÈÏÚ)，并删除了 thesaurus.txt 文件的第一行，但我仍然得到相同的 ascii 错误。 提前感谢您的帮助，我是 Python 的新手。 哦，这是代码，这样您就可以重新创建 ascii 错误（您可以从上面的链接下载 .txt 文件）。

import re
from random import *
file = open('thesaurus.txt', 'r')
# .lower() returns a version with all upper case characters replaced with lower case characters.
text = file.read().lower()
file.close()
# replaces anything that is not a lowercase letter, a space, or an apostrophe with a space:
text = re.sub('[^a-z\ \']+', " ", text)
words = list(text.split())

word = random.choice(words)

wordlist = list(word)

guess = []
prove = []

for l in range(len(word)):
    guess.append("_")
attempts_remaining = 6
print (guess)
print("You have", attempts_remaining, "attempts")
guessed = 0
while guessed < len(word) and attempts_remaining != 0:
    if attempts_remaining != 0:
        guessed_this_time = 0
        prova = input("Write a letter: ")
        prove.append(prova)

        if prove.count(prova) > 1:
            prova = input("You've already tried this letter! Try with another: ")


        for l in range(len(word)):


            if wordlist[l] == prova:

                guess[l] = wordlist [l]
                guessed += 1
                guessed_this_time += 1    


            else:
                pass
        if guessed_this_time == 0:
            attempts_remaining -= 1
            print(attempts_remaining, "attempts remaining")
        elif guessed == len(word):
            print("You guessed it!")
        print(guess)
    if attempts_remaining == 0:
        print("You lost, the word was", word)

错误是：

Traceback (most recent call last):
  File "/Users/user/Documents/Python/Impiccato/impiccato.py", line 5, in <module>
    text = file.read().lower()
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/encodings/ascii.py", line 26, in decode
    return codecs.ascii_decode(input, self.errors)[0]
UnicodeDecodeError: 'ascii' codec can't decode byte 0x88 in position 2170: ordinal not in range(128)

编辑：我“解决”了将所有 txt 内容移动到 .py 并以这种方式调用它：

text = """
here's all the list (the whole thing is 19414Ln LOL)
... """
words = \
re.sub('[^a-z\ \']+', " ", text).split() # Stores the secret words in a list

这样逗号被空格替换。

Answer 1

这是编码。我不知道该网站将其设置为什么，但它不是您想要的。只需在您喜欢的编辑器中打开它并将编码设置为UTF-8。由于另一个错误，它仍然无法正常工作：.count() not 不会为您提供项目数量。你想要len(words)。