PHP多维数组：如果子数组的最后一个则增加键

Question

对于日历，我从数据库中读取开始日期和结束日期，然后 dateRange 函数为每个键创建一个包含一天的数组，如下所示：

$total_dates[]=dateRange('2012-04-01','2012-04-05');
$total_dates[]=dateRange('2012-04-06','2012-04-09');
$total_dates[]=dateRange('2012-04-10','2012-04-15');
$total_dates[]=dateRange('2012-04-17','2012-04-21');
$total_dates[]=dateRange('2012-04-24','2012-04-28');

将输出：

Array (
[0] => Array ( [0] => 2012-04-01 [1] => 2012-04-02 [2] => 2012-04-03 [3] => 2012-04-04 [4] => 2012-04-05 )
[1] => Array ( [0] => 2012-04-06 [1] => 2012-04-07 [2] => 2012-04-08 [3] => 2012-04-09 )
[2] => Array ( [0] => 2012-04-10 [1] => 2012-04-11 [2] => 2012-04-12 [3] => 2012-04-13 [4] => 2012-04-14 [5] => 2012-04-15 )
[3] => Array ( [0] => 2012-04-17 [1] => 2012-04-18 [2] => 2012-04-19 [3] => 2012-04-20 [4] => 2012-04-21 )
[4] => Array ( [0] => 2012-04-24 [1] => 2012-04-25 [2] => 2012-04-26 [3] => 2012-04-27 [4] => 2012-04-28 )
)

现在它应该在包含在数组中并且在空闲日期可用的那些日期输出不可用。每天只能预约一次（目前，我以后也需要像早上和下午一样实现，所以这会交叉）。

逻辑是从第一天到最后一天。如果不是，echo free，如果是，检查是否是这个dateRange的最后一天，如果是，增加子数组的key...

这里是代码，但是如果是最后一个key就不会增加key...

reset($total_dates);
$array_i=0;


for ($i=1;$i<=$this_maxdays_month;$i++) {

if($i<10) {$i2="0".$i;} else {$i2=$i;} //if $i is 1-9, add a leading zero
if($i==1) {$month_begin=date('M',$this_date)." ";} else {$month_begin="";} //if 1st of month add e.g. Jan

if($total_dates[$array_i]) {
    if (in_array("$year-month-$i2",$total_dates[$array_i])) {
        echo "not available";

                // now check if the last key in date range, if yes, increase key -> does not work!
        if (key(array_slice($total_dates[$array_i], -1, 1, TRUE))+1==$i) {$array_i++;}

       }

    else {
        echo "available";

       }       
    }
}

PS：我也试过了：

$count_max_array_keys=count($total_dates[$array_i])+1;
if (!array_key_exists($count_max_array_keys,$total_dates[$array_i])) {$array_i++;}

并使用 +1（如第一个示例）...

...有人知道我在这里缺少什么吗？？

提前谢谢你！

---

更新：它应该输出（稍后在日历视图中构建），例如：

1st April 2012: booked
2nd April 2012: booked
3rd April 2012: booked (this is the last date of this dateRange, so increase key)
4th April 2012: (not in array anymore) available
5th April 2012: available
6th April 2012: (is in the next dateRange) booked
...

希望现在更清楚了，谢谢！

---

更新 2：如果我在与之前的 array_slice 完全相同的位置使用 if ( (count($total_dates[$array_i])-1)+1==$i) {$array_i++;}，则会发生以下情况：

row-number    $array_i    output of the count-statement
1: 0    4
2: 0    4
3: 0    4
4: 0    4
5: 1    3 (this is the last key, but here $array_i should still be 0, as the increase happens after the output, and why is suddenly count only 3?)
6-30: 1     3 (it never increases again)

Answer 1

我知道我没有您的完整代码，所以我重度重写了它，以便它可以独立执行。我希望这将帮助您找到问题的答案。

<?php
$total_dates = array();
$total_dates[]=array('2012-04-01','2012-04-02','2012-04-03','2012-04-04','2012-04-05');
$total_dates[]=array('2012-04-24','2012-04-25','2012-04-26','2012-04-27');

$this_maxdays_month = 30;
$year = "2012";
$month = "04";

function date_is_first_in_set($date, $total_dates)
{
    $ret = false;

    for($i = 0; $i < count($total_dates); $i++)
    {
        if($date == $total_dates[$i][0])
        {
            $ret = true;
            break;
        }
    }

    return $ret;
}

function date_is_last_in_set($date, $total_dates)
{
    $ret = false;

    for($i = 0; $i < count($total_dates); $i++)
    {
        if($date == end($total_dates[$i]))
        {
            $ret = true;
            break;
        }
    }

    return $ret;
}

function date_available($date, $total_dates)
{
    $ret = true;

    for($i = 0; $i < count($total_dates); $i++)
    {
        if(in_array($date, $total_dates[$i]))
        {
            $ret = false;
            break;
        }
    }

    return $ret;
}

for($i = 1; $i <= $this_maxdays_month; $i++)
{
    $date = $year.'-'.$month.'-'.str_pad($i, 2, '0', STR_PAD_LEFT);

    echo $date.': ';

    if(date_available($date, $total_dates))
    {
        echo 'available';
    }
    else
    {
        echo 'unavailable';
    }

    if(date_is_first_in_set($date, $total_dates))
    {
        echo ' FIRST!';
    }
    if(date_is_last_in_set($date, $total_dates))
    {
        echo ' LAST!';
    }

    echo "<br>\n";
}
?>

由此产生的输出将是：

2012-04-01: unavailable FIRST!
2012-04-02: unavailable
2012-04-03: unavailable
2012-04-04: unavailable
2012-04-05: unavailable LAST!
2012-04-06: available
2012-04-07: available
2012-04-08: available
2012-04-09: available
2012-04-10: available
2012-04-11: available
2012-04-12: available
2012-04-13: available
2012-04-14: available
2012-04-15: available
2012-04-16: available
2012-04-17: available
2012-04-18: available
2012-04-19: available
2012-04-20: available
2012-04-21: available
2012-04-22: available
2012-04-23: available
2012-04-24: unavailable FIRST!
2012-04-25: unavailable
2012-04-26: unavailable
2012-04-27: unavailable LAST!
2012-04-28: available
2012-04-29: available
2012-04-30: available