【发布时间】:2020-04-25 10:05:32
【问题描述】:
我正在学习如何使用 jq 来操作 json 数据, 我有点麻烦。 这是我的输入 JSON
{
"user":{
"advertisingID":"617a68"
},
"deviceTs":1575387020137,
"activies":[
{
"ts":1575617868326,
"appsUsage":{
"isFull":true,
"data":[
{
"com.orange.phone":44009
}
],
"startTs":1575617281541
}
},
{
"ts":1575618968326,
"appsUsage":{
"isFull":true,
"data":[
{
"uk.green.launcher2":4354
},
{
"com.black.phone":1232
}
],
"startTs":1575617281541
}
}
]
}
我想用“破折号”替换所有包含“点”的键 和预期的输出:
{
"user":{
"advertisingID":"617a68"
},
"deviceTs":1575387020137,
"activies":[
{
"ts":1575617868326,
"appsUsage":{
"isFull":true,
"data":[
{
"com-orange-phone":44009 <----
}
],
"startTs":1575617281541
}
},
{
"ts":1575618968326,
"appsUsage":{
"isFull":true,
"data":[
{
"uk-green-launcher2":4354 <----
},
{
"com-black-phone":1232 <----
}
],
"startTs":1575617281541
}
}
]
}
我试过了 .activies |= map( with_entries(if .key == "appsUsage" then ... else . end) ) ... (split(".")|join("-")) 但没有成功, 提前致谢。
【问题讨论】: