javascript中的重复功能（石头，纸，剪刀）

Question

我是 javascript 和一般编码方面的初学者，我刚刚制作了一个石头、纸、剪刀游戏，您可以在其中重新选择是否平局。 我希望函数在第 15 行之后重复（当然，如果条件为真），但我不知道该怎么做...... 所以如果有平局，你应该重新选择（这可行），但是在重新选择之后，计算机的选择的生成应该重复并且与 compare() 函数相同，以使系统重新选择- 选择工作。

var userChoice = prompt("Do you choose rock, paper or scissors?");

var computerChoice = Math.random();
if (computerChoice < 0.34) {
    computerChoice = "rock";
} else if (computerChoice <= 0.67) {
    computerChoice = "paper";
} else {
    computerChoice = "scissors";
} 

var compare = function(choice1, choice2) {
 if (choice1 === choice2) {
     console.log("The result is a tie, please re-choose!")
     userChoice = prompt("Do you choose rock, paper or scissors?");
 } else if (choice1 === "rock") {
     if (choice2 === "scissors") {
         return "rock wins";
     } else {
         return "paper wins";
     }
 } else if (choice1 === "paper") {
     if (choice2 === "rock") {
         return "paper wins";
     } else {
         return "scissors wins";
     }
 } else {
     if (choice2 === "rock") {
         return "rock wins";
     } else {
         return "scissors wins";
     }
 }
};

compare(userChoice, computerChoice);

Answer 1

您可以为选择过程创建一个函数，然后在比较中调用它：

var userChoice, computerChoice;

var choose = function() {
    userChoice = prompt("Do you choose rock, paper or scissors?");

    var computerChoice = Math.random();
    if (computerChoice < 0.34) {
        computerChoice = "rock";
    } else if (computerChoice <= 0.67) {
        computerChoice = "paper";
    } else {
        computerChoice = "scissors";
    } 
}


var compare = function(choice1, choice2) {
    if (choice1 === choice2) {
        console.log("The result is a tie, please re-choose!")
        choose();                                   // Choose again
        return compare(userChoice, computerChoice); // Compare again, recursively!
    } else if (choice1 === "rock") {
        ...
    }
    ...
};

choose();                             // Make the choice
compare(userChoice, computerChoice);  // Compare

或者，如果您不想使用递归，您可以return "tie"; 以防出现平局，然后重复该过程直到平局解决：

var choose = function() {
    // As above
    ...
}

var compare = function(choice1, choice2) {
    if (choice1 === choice2) {
        console.log("The result is a tie, please re-choose!")
        return "tie"; // Tie occurred
    }
    ...
};


var result;

do {
    choose();                                     // Choose an item
    result = compare(userChoice, computerChoice); // Compare the choices
} while(result != "tie");                         // Repeat until ties are resolved

Answer 2

只使用递归：

 if (choice1 === choice2) {
     console.log("The result is a tie, please re-choose!")
     userChoice = prompt("Do you choose rock, paper or scissors?");
     compare( userChoice, choice2 );
 } else if (choice1 === "rock") {

Answer 3

我最近在 CodeAcademy 开始使用 JavaScript 并遇到了同样的问题， John 的回答是正确的，尽管它需要进行一些更正才能起作用。

这部分，我们调用choice()然后调用compare(userChoice,computerChoice)函数，变量userChoice和computerChoice在choose函数内部声明，使它们成为局部变量，不能从代码的最后一行调用.

您需要做的唯一更改是您需要在选择函数中调用 compare(userChoice,computerChoice) 然后它就可以正常工作了！

这是对我有用的完整代码。

   var choice = function()
        {
                var userChoice = prompt("Select rock, paper, scissors");
                var computerChoice = Math.random();

                if(computerChoice<=0.33){
                    computerChoice = "rock";
                }
                else if(computerChoice<=0.67){
                    computerChoice = "paper";
                }
                else{
                    computerChoice = "scissors";
                }
                alert("The Computer's choice is:- "+computerChoice);
                var answer = compare(userChoice,computerChoice);
                alert(answer);


        };

        var compare = function(choice1,choice2)
        {
            if(choice1===choice2)
            {
                alert("It's a tie! You must select another choice!");
                choice();
                return compare(userChoice,computerChoice);
            }

            else if(choice1==="rock")
            {
                if(choice2==="scissors")
                {
                    return("Rock wins! You've won!");
                }
                else
                {
                    return("Paper wins! You lose!");
                }
            }
            else if(choice1==="paper")
            {
                if(choice2==="rock")
                {
                    return("paper wins! You've won!");
                }
                else
                {
                    return("Scissors wins! You lose!");
                }
            }
            else if(choice1==="scissors")
            {
                if(choice2==="paper")
                {
                    return("Scissors wins! You've won!");
                }
                else
                {
                    return("Rock wins! You lose!");
                }
            }
        };
        choice();