在每行上打印有限数量的列表（python）答案

【问题标题】：print la limited number of list on each line (python)在每行上打印有限数量的列表（python）
【发布时间】：2020-11-08 08:19:14
【问题描述】：

打印列表中的元素，每行 10 位从此

n = [85, 13, 99, 34, 71, 15, 82, 24, 64, 61,
     67, 99, 50, 68, 25, 37, 32, 27, 14, 91,
     79, 15, 47, 48, 74, 88, 64, 53, 77, 50,
     24, 91, 87, 55, 60, 75, 91, 22, 47, 63,
     81, 88, 26, 48, 69, 59, 84, 77, 28, 36,
     59, 74, 89, 73, 91, 64, 55, 88, 90, 48,
     73, 97, 98, 40, 93, 50, 78, 60, 44, 77,
     82, 51, 53, 65, 98, 59, 94, 91, 52, 44,
     65, 85, 72, 92, 49, 67, 58, 48, 62, 54,
     89, 67, 58, 48, 85, 45, 77, 76, 81, 77]

到这里（不带括号）

value n :
85, 13, 99, 34, 71, 15, 82, 24, 64, 61, 
67, 99, 50, 68, 25, 37, 32, 27, 14, 91, 
79, 15, 47, 48, 74, 88, 64, 53, 77, 50, 
24, 91, 87, 55, 60, 75, 91, 22, 47, 63, 
81, 88, 26, 48, 69, 59, 84, 77, 28, 36, 
59, 74, 89, 73, 91, 64, 55, 88, 90, 48, 
73, 97, 98, 40, 93, 50, 78, 60, 44, 77, 
82, 51, 53, 65, 98, 59, 94, 91, 52, 44, 
65, 85, 72, 92, 49, 67, 58, 48, 62, 54, 
89, 67, 58, 48, 85, 45, 77, 76, 81, 77

【问题讨论】：

标签： python list printing formatting

【解决方案1】：

你可以试试这个：

n = [85, 13, 99, 34, 71, 15, 82, 24, 64, 61,
     67, 99, 50, 68, 25, 37, 32, 27, 14, 91,
     79, 15, 47, 48, 74, 88, 64, 53, 77, 50,
     24, 91, 87, 55, 60, 75, 91, 22, 47, 63,
     81, 88, 26, 48, 69, 59, 84, 77, 28, 36,
     59, 74, 89, 73, 91, 64, 55, 88, 90, 48,
     73, 97, 98, 40, 93, 50, 78, 60, 44, 77,
     82, 51, 53, 65, 98, 59, 94, 91, 52, 44,
     65, 85, 72, 92, 49, 67, 58, 48, 62, 54,
     89, 67, 58, 48, 85, 45, 77, 76, 81, 77]

print("value n :")

for x in range(10):
    print(', '.join([str(num) for num in (n[x*10:x*10+10])]))

输出：

value n : 
85, 13, 99, 34, 71, 15, 82, 24, 64, 61
67, 99, 50, 68, 25, 37, 32, 27, 14, 91
79, 15, 47, 48, 74, 88, 64, 53, 77, 50
24, 91, 87, 55, 60, 75, 91, 22, 47, 63
81, 88, 26, 48, 69, 59, 84, 77, 28, 36
59, 74, 89, 73, 91, 64, 55, 88, 90, 48
73, 97, 98, 40, 93, 50, 78, 60, 44, 77
82, 51, 53, 65, 98, 59, 94, 91, 52, 44
65, 85, 72, 92, 49, 67, 58, 48, 62, 54
89, 67, 58, 48, 85, 45, 77, 76, 81, 77

【讨论】：

【解决方案2】：

y = [", ".join([str(x) for x in n[10*(i-1):10*i]]) for i in range(1, 11)]
print("\n".join(y))

我首先将原始列表拆分为 10 个子列表，将每个子列表变成一个字符串，然后将这些字符串连接起来。

【讨论】：

【解决方案3】：

您可以使用separator in print 获得所需的输出

print('value n :')
for i in range(0, len(n), 10):
    print(*n[i:i+10], sep = ', ')

说明

range(0, len(n), 10) 在每一行创建起始索引
n[i:i+1] 是每行包含 10 个值的数组
*n[i:i+1] 是将列表 n[i:i+1 转换为 print 的位置参数的解包运算符（即等效于 print(n[i], n[i+1], . ..n[i+10])
sep = ', ' 使每个位置参数都用逗号分隔符打印

【讨论】：

【解决方案4】：

输入：

n = [85, 13, 99, 34, 71, 15, 82, 24, 64, 61,
     67, 99, 50, 68, 25, 37, 32, 27, 14, 91,
     79, 15, 47, 48, 74, 88, 64, 53, 77, 50,
     24, 91, 87, 55, 60, 75, 91, 22, 47, 63,
     81, 88, 26, 48, 69, 59, 84, 77, 28, 36,
     59, 74, 89, 73, 91, 64, 55, 88, 90, 48,
     73, 97, 98, 40, 93, 50, 78, 60, 44, 77,
     82, 51, 53, 65, 98, 59, 94, 91, 52, 44,
     65, 85, 72, 92, 49, 67, 58, 48, 62, 54,
     89, 67, 58, 48, 85, 45, 77, 76, 81, 77]

代码：

    print('value n:')
    for i in range(0, n.__len__(), 10):
        print(*n[i:i+10], sep=', ',end='\n')

输出：

value n:
85, 13, 99, 34, 71, 15, 82, 24, 64, 61
67, 99, 50, 68, 25, 37, 32, 27, 14, 91
79, 15, 47, 48, 74, 88, 64, 53, 77, 50
24, 91, 87, 55, 60, 75, 91, 22, 47, 63
81, 88, 26, 48, 69, 59, 84, 77, 28, 36
59, 74, 89, 73, 91, 64, 55, 88, 90, 48
73, 97, 98, 40, 93, 50, 78, 60, 44, 77
82, 51, 53, 65, 98, 59, 94, 91, 52, 44
65, 85, 72, 92, 49, 67, 58, 48, 62, 54
89, 67, 58, 48, 85, 45, 77, 76, 81, 77

【讨论】：