【问题标题】:Validating xml with xsd using JDOM使用 JDOM 使用 xsd 验证 xml
【发布时间】:2013-11-22 10:34:26
【问题描述】:

您好,我正在尝试使用 JDOM 验证带有 xsd 的 xml。 这是我的验证代码:-

public class jdom1 {

    public static void main(String[] args) throws JDOMException, IOException {

        // TODO Auto-generated method stub
        File xsdfile = new File("file.xsd");
        XMLReaderJDOMFactory schemafac = new XMLReaderXSDFactory(xsdfile);
        SAXBuilder builder = new SAXBuilder(schemafac);
        Document doc =  builder.build(new File("file.xml"));
        Element root = doc.getRootElement();
        for(Element testCase : root.getChildren()){
            //Code

    }

}

我的文件.xml :-

<?xml version="1.0" encoding="UTF-8"?>


<document>
 <testCaseDataName>
  <id>1</id >
  <testCaseName>Edit</testCaseName >
  <expectedResult>true</expectedResult >

 </testCaseDataName>
 <testCaseDataName>
  <id>2</id >
  <testCaseName>add</testCaseName >
  <expectedResult>false</expectedResult>
  <parameter>
    <key>featues</key >
    <value>w,f</value>
    </parameter>
 </testCaseDataName>

  <testCaseDataName>
  <id>3</id >
  <testCaseName>delete</testCaseName >
  <expectedResult>duplicate</expectedResult>
  <parameter>
    <key>projectType</key >
    <value>new</value>
    <key>Name</key >
    <value>mashnew</value>
    <key>status</key >
    <value>ACTIVE</value>
    <key>canOrder</key >
    <value>Yes</value>
    </parameter>
 </testCaseDataName>
 </document>

我的文件.xsd :-

<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
    targetNamespace="http://www.example.org/ACL"
    xmlns:tns="http://www.example.org/ACL"
    elementFormDefault="qualified">
    <include schemaLocation=""></include>
    <element name="document">
    <complexType>
      <sequence>
    <element name="testCaseDataName">
     <complexType>
      <sequence>
        <element name ="id" type ="ID" ></element>
        <element name ="testCaseName" type ="string" ></element>
        <element name = "expectedResult" type="string"></element>
        <element name = "parameter" minOccurs="0">
        <complexType>
            <sequence>
                <element name="key" type ="string" maxOccurs="1"></element>
                <element name="value" type="string" maxOccurs="unbounded"></element>
            </sequence>
        </complexType>
        </element>
        </sequence>
     </complexType>
    </element>
    </sequence>
    </complexType>
    </element>
</schema>

当我运行此代码时,我收到以下错误。谁能帮我解决这个问题。

Exception in thread "main" org.jdom2.input.JDOMParseException: Error on line 4 of document file:/C:/Users/file.xml: cvc-elt.1: Cannot find the declaration of element 'document'.
    at org.jdom2.input.sax.SAXBuilderEngine.build(SAXBuilderEngine.java:228)
    at org.jdom2.input.sax.SAXBuilderEngine.build(SAXBuilderEngine.java:277)
    at org.jdom2.input.sax.SAXBuilderEngine.build(SAXBuilderEngine.java:264)
    at org.jdom2.input.SAXBuilder.build(SAXBuilder.java:1116)
    at com.memoir.client.test.testdb.jdom1.main(jdom1.java:24)
Caused by: org.xml.sax.SAXParseException: cvc-elt.1: Cannot find the declaration of element 'document'.
    at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
    at org.apache.xerces.util.ErrorHandlerWrapper.error(Unknown Source)
    at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
    at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
    at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
    at org.apache.xerces.impl.xs.XMLSchemaValidator.handleStartElement(Unknown Source)
    at org.apache.xerces.impl.xs.XMLSchemaValidator.startElement(Unknown Source)
    at org.apache.xerces.impl.XMLNSDocumentScannerImpl.scanStartElement(Unknown Source)
    at org.apache.xerces.impl.XMLNSDocumentScannerImpl$NSContentDispatcher.scanRootElementHook(Unknown Source)
    at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
    at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
    at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
    at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
    at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
    at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
    at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
    at org.jdom2.input.sax.SAXBuilderEngine.build(SAXBuilderEngine.java:217)
    ... 4 more

【问题讨论】:

    标签: java xml xsd


    【解决方案1】:

    这是进行验证的方法,请检查您的代码

    SchemaFactory schemafac =
         SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
         Schema schema = schemafac.newSchema(new File("myschema.xsd"));
         XMLReaderJDOMFactory factory = new XMLReaderSchemaFactory(schema);
         SAXBuilder sb = new SAXBuilder(factory);
         Document doc = sb.build(new File("file.xml"));
    

    使用下面的架构

    <xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
      <xs:element name="document">
        <xs:complexType>
          <xs:sequence>
            <xs:element name="testCaseDataName" maxOccurs="unbounded" minOccurs="0">
              <xs:complexType>
                <xs:sequence>
                  <xs:element type="xs:byte" name="id"/>
                  <xs:element type="xs:string" name="testCaseName"/>
                  <xs:element type="xs:string" name="expectedResult"/>
                  <xs:element name="parameter" minOccurs="0">
                    <xs:complexType>
                      <xs:choice maxOccurs="unbounded" minOccurs="0">
                        <xs:element type="xs:string" name="key"/>
                        <xs:element type="xs:string" name="value"/>
                      </xs:choice>
                    </xs:complexType>
                  </xs:element>
                </xs:sequence>
              </xs:complexType>
            </xs:element>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
    </xs:schema>
    

    【讨论】:

    • 我仍然遇到同样的错误。你能看看我的xml和xmd是否正确吗?
    • 让我试试看一下
    • 你能试试新架构吗
    【解决方案2】:

    我的架构错误。使用此http://www.freeformatter.com/xsd-generator.html 生成模式并且验证工作正常。谢谢

    【讨论】:

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