Sinon：类的存根静态方法无法按预期工作答案

【问题标题】：Sinon: Stubbing static method of class does not work as expectedSinon：类的存根静态方法无法按预期工作
【发布时间】：2018-10-14 13:32:37
【问题描述】：

我想模拟以下类，用作另一个类的依赖项：

module.exports = class ResponseHandler {

static response(res, status_, data_, codes_) {
    console.log('Im here. Unwillingly');
    // doing stuff here...
};

ResponseHandler 由 ProfileController 导入并在那里使用：

const response = require('../functions/tools/response.js').response;

module.exports = class ProfileController {

static async activateAccountByVerificationCode(req, res) {
    try{
        // doing stuff here
        return response(res, status.ERROR, null, errorCodes);
    }
}

现在我正在为 ProfileController 编写单元测试，我正在测试 activateAccountByVerificationCode 是否使用给定的参数调用 response

describe('ProfileController', () => {

    let responseStub;

    beforeEach(function() {

        responseStub = sinon.stub(ResponseHandler, 'response').callsFake(() => null);
    });

但尽管 response 被模拟，ProfileController 仍然调用响应的真正实现（参见控制台输出：'Im here. Unwillingly'）

    it('should respond accordingly if real verification code does not fit with the one passed by the user', async function () {
        // here you can still see that real implementation is still called
        // because of console output 'I'm here unwillingly'
        await controller.activateAccountByVerificationCode(req, res);

        console.log(responseStub.called); // -> false
        expect(responseStub.calledWith(res, status.ERROR, null, [codes.INVALID_VERIFICATION_CODE])).to.eql(true); // -> negative
    });

【问题讨论】：

标签： javascript class testing static sinon

【解决方案1】：

您需要先使用 proxyquire 之类的库模拟控制器依赖项，然后在测试中使用此模拟实例。否则，您仍将使用原始（未存根）实现。

const proxyquire = require('proxyquire');

describe('ProfileController', () => {

    let responseStub;
    let Controller;

    beforeEach(function() {

        responseStub = sinon.stub(ResponseHandler, 'response').callsFake(() => null);
        Controller = proxyquire('./ProfileController', {'../functions/tools/response':responseStub})
    });

    it('should respond accordingly if real verification code does not fit with the one passed by the user', async function () {
        // here you can still see that real implementation is still called
        // because of console output 'I'm here unwillingly'
        await Controller.activateAccountByVerificationCode(req, res);

        console.log(responseStub.called); // -> false
        expect(responseStub.calledWith(res, status.ERROR, null, [codes.INVALID_VERIFICATION_CODE])).to.eql(true); // -> negative
    });

Controller 然后使用你的函数的存根版本并且可以被检查。

【讨论】：