如果我的布尔值始终为真，我将如何检查单个灯

Question

如果 boolean 为真，我需要一种方法来检查所有脚本，然后在此脚本中使用一种方法来查看当前灯的 if 语句中角色站在旁边的 boolean true 才能激活，然后才应该实例化函数被触发。

private bool Once = true;
public Transform Spawnpoint1;
public Transform Spawnpoint2;

public GameObject Prefab1;
public GameObject Prefab2;

//Something like this, but I don't know where to go after that
GameObject[] Lights = GameObject.FindGameObjectsWithTag("lightSwitch");
//foreach(GameObject Light in Lights)

void OnTriggerEnter2D(Collider2D collision)
{
    if (Once == true)
    {
        Debug.Log("It's true");
        if (LightOnOff.isON == true) // It needs to check this constantly
        {
            Debug.Log(" It's Lit");
            Instantiate(Prefab1, Spawnpoint1.position, Spawnpoint1.rotation);

            Instantiate(Prefab2, Spawnpoint2.position, Spawnpoint2.rotation);

            Once = false;
        }
    }
}

这里也是 Light 脚本

public static bool isON;

public void lightOn()
{
    this.GetComponent<Light>().enabled = true;
    isON = true;
}

Answer 1

首先你不应该使用static

public static bool isON;

个人价值！ static 使该值成为“非实例化”值，这意味着它属于整个类而不是实例 => 简单地说，这个变量在所有组件之间共享（有关更多信息，请参阅 this post）。而是使用

public bool isON;

---

比像访问组件的实例变量
更新：从 cmets 我现在知道实际上组件不在对撞机对象上，而是在该脚本附加到的对象的子对象上

void OnTriggerEnter2D(Collider2D collision)
{
    // Update. TODO check if the correct Object collided
    //if(!collision.gameObject == <your player>)

    if (!Once) return;

    // Update this now searches in its own children instead of children of collision
    var lightOnOff = GetComponentInChildren<LightOnOff>(true);
    if(!lightOnOff)
    {
        Debug.Log("No LightOnOff found on collision" + collision.name, this);
        return;
    }

    Debug.Log("It's true");
    if (!LightOnOff.isON) return;

    Debug.Log(" It's Lit");
    Instantiate(Prefab1, Spawnpoint1.position, Spawnpoint1.rotation);
    Instantiate(Prefab2, Spawnpoint2.position, Spawnpoint2.rotation);

    Once = false;
}

---

但是，除了使用 LightOnOff 组件，您还可以简单地访问 Light 组件并执行类似
更新：从 cmets 我现在知道实际上组件不在对撞机对象上而是在此脚本附加到的对象的子对象上

void OnTriggerEnter2D(Collider2D collision)
{
    if (!Once) return;

    // directly access the Light
    // Update this now searches in its own children instead of children of collision
    var light = GetComponentInChildren<Light>(true);
    if(!light)
    {
        Debug.Log("No Light found on collision" + collision.name, this);
        return;
    }

    Debug.Log("It's true");

    // Directly check if the Light component is enabled
    if (!light.enabled) return;

    Debug.Log(" It's Lit");
    Instantiate(Prefab1, Spawnpoint1.position, Spawnpoint1.rotation);
    Instantiate(Prefab2, Spawnpoint2.position, Spawnpoint2.rotation);

    Once = false;
}

Answer 2

您无需为此跟踪所有灯光。

你需要改变的是你应该让isON 不是静态的。这是因为实际的灯可能亮或不亮，而不是灯的概念是否亮。

public bool isON;

检查 Collider2D 是否与您正在碰撞的关联对象，并在那里寻找灯光。以下代码假定任何灯光都将位于与触发器或其子之一相同的 GameObject 上。

void OnCollisionEnter2D(Collider2D col) {
    // only activate once
    if (once) {
        // Get light if exists
        GameObject collidedObject = col.gameObject;
        Light light = collidedObject.GetComponentInChildren<Light>();

        if (light != null) {
            // We have a light, check if it's on. We only care about the collided light
            if (light.isON) {
                Debug.Log("It's Lit fam");

                Instantiate(Prefab1, Spawnpoint1.position, Spawnpoint1.rotation);
                Instantiate(Prefab2, Spawnpoint2.position, Spawnpoint2.rotation);

                // Note that if we run into another lit light nothing will happen, 
                // even if its the first time running into that particular light
                Once = false;
            }
        }
    }
}

另外，您可以只使用if(something) 而不是if(something == true)