如何从键值对数组中获取对象数组答案

【问题标题】：How to get an array of objects from an array of key-value pair arrays如何从键值对数组中获取对象数组
【发布时间】：2018-02-02 02:01:33
【问题描述】：

我有一个这样的数组：

var arr = 
[
["Id", "0011900000YDtPXAA1"],
["Name", "account 50"],
["OwnerId", "005190000023IPPAA2"],
["Industry", "Manufacturing"],
["Phone", "312-552-4450"],
["Id", "0011900000YDtPbAAL"],
["Name", "account 54"],
["OwnerId", "005190000023IPPAA2"],
["Industry", "Manufacturing"],
["Phone", "312-552-4454"]
]

我需要每个子数组是一个包含一个键值对的对象。

[
{"Id": "0011900000YDtPXAA1"},
{"Name": "account 50"},
...
]

我试过了

var objArr = new Map(arr);

这会生成我需要的键值对，但会将它们全部放在同一个对象中。如何获得一组由一对 k-v 组成的较小对象？

【问题讨论】：

标签： javascript arrays object dictionary

【解决方案1】：

我会这样做：

1。箭头函数

var arr = [
  ["Id", "0011900000YDtPXAA1"],
  ["Name", "account 50"],
  ["OwnerId", "005190000023IPPAA2"],
  ["Industry", "Manufacturing"],
  ["Phone", "312-552-4450"],
  ["Id", "0011900000YDtPbAAL"],
  ["Name", "account 54"],
  ["OwnerId", "005190000023IPPAA2"],
  ["Industry", "Manufacturing"],
  ["Phone", "312-552-4454"]
];

const newArr = arr.map(innerArr => ({[innerArr[0]]: innerArr[1]}));

console.log(newArr);

2。不是箭头函数

var arr = [
  ["Id", "0011900000YDtPXAA1"],
  ["Name", "account 50"],
  ["OwnerId", "005190000023IPPAA2"],
  ["Industry", "Manufacturing"],
  ["Phone", "312-552-4450"],
  ["Id", "0011900000YDtPbAAL"],
  ["Name", "account 54"],
  ["OwnerId", "005190000023IPPAA2"],
  ["Industry", "Manufacturing"],
  ["Phone", "312-552-4454"]
];

const newArr = arr.map(function (innerArr) { return {[innerArr[0]]: innerArr[1]}; });

console.log(newArr);

map() 方法创建一个新数组，其结果是在调用数组中的每个元素上调用提供的函数。

【讨论】：

您有语法错误。 {innerArr[0]: innerArr[1]} 应该是 {[innerArr[0]]: innerArr[1]}。
我在您编辑后使用了箭头功能。它完美地工作。谢谢！

【解决方案2】：

您可以为此使用传统的 for 循环

var arr = [
  ["Id", "0011900000YDtPXAA1"],
  ["Name", "account 50"],
  ["OwnerId", "005190000023IPPAA2"],
  ["Industry", "Manufacturing"],
  ["Phone", "312-552-4450"],
  ["Id", "0011900000YDtPbAAL"],
  ["Name", "account 54"],
  ["OwnerId", "005190000023IPPAA2"],
  ["Industry", "Manufacturing"],
  ["Phone", "312-552-4454"]
];

var arr2 = [];

for (var i = 0; i < arr.length; i++) {

  var sub = {};
  
  sub[arr[i][0]] = arr[i][1];

  arr2.push(sub);

}

console.log(arr2);

【讨论】：