这是另一种方法，它使用strchr()，但这假设输入字符串始终具有格式
name: item1,item2,item3,...,itemN
这是程序
#include <string.h>
#include <stdio.h>
int
main(void)
{
const char *const string = "file1.h: file2.c,file3.cpp ";
const char *head;
const char *tail;
const char *next;
// This basically makes a pointer to the `:'
head = string;
// If there is no `:' this string does not follow
// the assumption that the format is
//
// name: item1,item2,item3,...,itemN
//
if ((tail = strchr(head, ':')) == NULL)
return -1;
// Save a pointer to the next character after the `:'
next = tail + 1;
// Strip leading spaces
while (isspace((unsigned char) *head) != 0)
++head;
// Strip trailing spaces
while (isspace((unsigned char) *(tail - 1)) != 0)
--tail;
fputc('*', stdout);
// Simply print the characters between `head' and `tail'
// you could as well copy them, or whatever
fwrite(head, 1, tail - head, stdout);
fputc('*', stdout);
fputc('\n', stdout);
head = next;
while (head != NULL) {
tail = strchr(head, ',');
if (tail == NULL) {
// This means there are no more `,'
// so we now try to point to the end
// of the string
tail = strchr(head, '\0');
}
// This is basically the same algorithm
// just with a different delimiter which
// will presumably be the same from
// here
next = tail + 1;
// Strip leading spaces
while (isspace((unsigned char) *head) != 0)
++head;
// Strip trailing spaces
while (isspace((unsigned char) *(tail - 1)) != 0)
--tail;
// Here is where you can extract the string
// I print it surrounded by `*' to show that
// it's stripping white spaces
fputc('*', stdout);
fwrite(head, 1, tail - head, stdout);
fputc('*', stdout);
fputc('\n', stdout);
// Try to point to the next one
// or make head `NULL' if this is
// the end of the string
//
// Note that the original `tail' pointer
// that was pointing to the next `,' or
// the end of the string, has changed but
// we have saved it's original value
// plus one, we now inspect what was
// there
if (*(next - 1) == '\0') {
head = NULL;
} else {
head = next;
}
}
fputc('\n', stderr);
return 0;
}
为了引导读者，注释过多。