【发布时间】:2017-04-12 21:06:00
【问题描述】:
我在我的应用程序中使用 express-graphql 和 node-fetch。我正在尝试将 graphql 与我的 api 调用一起使用来获取数据。目前我正在做
const QueryType = new GraphQLObjectType({
name: "Query",
fields: () => ({
acctsFromRelation: {
type: new GraphQLList(AcctType),
args: {
id: {type: GraphQLString},
status: {type: GraphQLString}
},
resolve: (root, args) => getOpIds(args)
}
})
});
AcctType如下
const AcctType = new GraphQLObjectType({
name: "acct",
fields: () => ({
id: {type: GraphQLString},
name: {type: GraphQLString},
clientType: {type: GraphQLString},
accountStatus: {type: GraphQLString,
args: {
status: {type: GraphQLString}
}},
primaryContact: {type: contactType},
billingAddress: {type: billingType}
})
});
我正在尝试做这样的事情:
{ acctsFromRelation (id: "2") {
id
name
accountStatus (status: "active")
primaryContact {
firstName
lastName
phone
email
}
billingAddress {
address1
address2
city
state
postalCode
country
}
}
}
我获取所有 id 为 2 且 accountStatus 为 active 的帐户。
GetOpIds如下:
function getOpIds (ids) {
return fetch(API CALL THAT GIVES IDS)
.then(res => res.json())
.then(json => json.map((element) => getAccountByUrl(element.id)))
.catch(err => err)
}
getAccountByUrl 看起来像这样
function getAccountByUrl (ids) {
return fetch(URL THAT LOOKS UP 1 ID at a TIME)
.then(res => res.json())
.then(json => json)
.catch(err => err)
}
【问题讨论】:
标签: javascript express graphql